For this case we have the following polynomial:
We must find the greatest common factor of the terms of the polynomial.
The GCF of the coefficients is given by:
Then we look for the GFC of the variables:
We have then:
Finally rewriting we have:
Answer:
the complete factored form of the polynomial is:
Answer:
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Step-by-step explanation:
legs of the triangles
Each triangle 30-60-90 is:
one leg: 15 ft => short diagonal = 2 * 15ft = 30ft
other leg, x:
tan(30) = 15 / x => x = 15 ft / tan(30) = 25.98 ft
=> long diagonal = 2 * 25.98ft = 51.96 ft
side of the rhoumbus = hypotenuse of one triangle
side of the rhombus = √ [ (15)^2 + (25.98)^2 ] = √(900) = 30 ft
Area of the rhombus:
4 * area of one triangle = 4 [base*height/2] = 4*15*25.98/2 = 779.43 ft^2
The shortest distance accross the garden is equal to the side of the rhombus = 30 ft
1.89 * 10^12
1.89e +12
e is shorthand for *10^(
