What is the slope of the line shown? Answers A: 3 B:2 C:1/2 D:-3

Mathematics

2 answers:

satela [25.4K]2 years ago

7 0

Answer:

-3

Step-by-step explanation:

Gnesinka [82]2 years ago

3 0

1/2 because slope is rise over run and it is rising 2 and going over 4 which simplifies to 1/2

You might be interested in

The diagram shows rays of light from a point source, P, that reach a detector, D, along two paths. One path is a straight line,

tatiyna

This can solved using the cosine law which is:
c² = a² + b² - 2ab cos θ
Using the values given from the problem
6² = b² + b² - 2bb cos 112.62
And solving for b
36 = 2b² - 2b² cos 112.62
b = 3.6

The answer is the 3rd option.

8 0

2 years ago

Read 2 more answers

Wilcorp has 50 employees who work 40 hours a week and earn $20/hour. Fifteen employees each worked 4 hours of overtime at 50% ab

tatuchka [14]

50 X (40 X$20) = 50 X $800 = $40,000

15 X (4 X (50% X $20+ $50)) = 15 X (4 X $60) = 15 X 240 = $3600

$40,000 + $3600 = $43,600 Total payroll

$3,600/$43,600 = .0825688073 as a percent rounded to the nearest tenth is 8.3%

3 0

2 years ago

To complete

natulia [17]

To figure this question out, we first need to figure out how much one pound of potatoes costs. To do this, we need to divide 18 by 8, and in this, we get $2.25. Then, we have to multiply this by 15 to find out how much 15 pounds of potatoes costs. This gives us $33.75, which is our answer to this question.

3 0

3 years ago

Recently a sample of 36 pieces of thread showed a mean breaking strength of 8.93 oz. Can one conclude at a significance level of

Deffense [45]

Complete Question

It has been found from experience that the mean breaking strength of a particular brand of thread is 9.72 oz with a standard deviation of 1.4 oz. Recently a sample of 36 pieces of thread showed a mean breaking strength of 8.93 oz. Can one conclude at a significance level of (a) 0.05, (b) 0.01 that the thread has become inferior?

Answer:

At both $\alpha = 0.05$ and $\alpha = 0.01$ the conclusion is that the thread has become inferior