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nekit [7.7K]
3 years ago
13

I need help with these 2 questions.

Mathematics
1 answer:
Natalka [10]3 years ago
7 0
I only see one questio but the answer to this one is a^2/b
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The fact that financial services are more plentiful and easier to access means that
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<span> Not 100% sure but I think it is: consumers need to be better informed about what services are available and what those services cost.</span>
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1. Segment A'B' is parallel to segment AB. What is the length of segment BB'?
ella [17]

Answer:

A. 3.5

Step-by-step explanation:

Given that AB is parallel to A'B', therefore,

CB/CB' = CA/CA'

CB' = 7

CB = CB' + BB' = 7 + BB'

CA' = 6

CA = CA' + AA' = 6 + 3 = 9

Plug in the values

(7 + BB')/7 = 9/6

(7 + BB')/7 = 3/2

Cross multiply

2(7 + BB') = 7(3)

14 + 2BB' = 21

Subtract 14 from both sides

2BB' = 21 - 14

2BB' = 7

Divide both sides by 2

BB' = 7/2

BB' = 3.5

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3 years ago
Find the seperate equation of lines represented by:<br><br>2x^2 - xy - 3y^2 =0​
Andreyy89
2x*2-xy-3y^2= 2943..
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3 years ago
Students were discussing what they had learned about minerals. They were debating the similarities of cleavage and fracture. Whi
Kobotan [32]

Answer:

C

Step-by-step explanation:

(i think)

4 0
3 years ago
Read 2 more answers
Solve the simultaneous equations<br> 4x + 3y = 20<br> 4x + 2y = 14
fiasKO [112]

Step-by-step explanation:

\underline{ \underline{ \text{Given}}} :

  • \tt{4x + 3y = 20...........  \text{ equation \: ( \: i \: )}}
  • \tt{4x + 2y = 14.......... \text{equation \: (ii)}}

\underline{ \text{USE \: ELIMINATION  \: METHOD}} :

Subtract equation ( ii ) from equation ( i ) :

Remember that the sign of each term of the second expression changes i.e equation ( i ) now becomes -4x -3y = -20

\tt{ \cancel{4x }+ 2y = 14}

\tt{ \cancel{ -  4x} -  3y =  - 20}

__________________

\tt{ - y =  - 6}

⟿ \tt{ \boxed{ \tt{y =  6}}}

Again , Substituting the value of y in equation ( ii ) :

⟿ \tt{4x + 2 \times 6 = 14}

⟿ \tt{4x + 12 = 14}

⟿ \tt{4x = 2}

⟿ \boxed{ \tt{x =  \frac{1}{2}}}

\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : x =  \frac{1}{2 }  \: and \: y = 6}}}}

Hope I helped ! ツ

Have a wonderful day / night ! ♡

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8 0
3 years ago
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