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adell [148]
3 years ago
10

Simplify fourth root of 6 over fifth root of 6.

Mathematics
2 answers:
grigory [225]3 years ago
8 0

Answer:

\sqrt[20]{6}

Step-by-step explanation:

we need to simplify

\frac{\sqrt[4]{5}}{\sqrt[5]{6}}

Each radical can be written in fraction form

\sqrt[4]{6} = 6^{\frac{1}{4}}

\sqrt[5]{6} = 6^{\frac{1}{5}}

\frac{\sqrt[4]{5}}{\sqrt[5]{6}}=\frac{6^{\frac{1}{4}}}{6^{\frac{1}{5}}}

Both top and bottom have same base so we subtract the exponents

6^{\frac{1}{4} -\frac{1}{5}}

Take common denominator to subtract the fractions

\frac{1*5}{4*5} -\frac{1*4}{5*4}

\frac{5-4}{20} =\frac{1}{20}

6^{\frac{1}{4} -\frac{1}{5}}=6^\frac{1}{20}

6^\frac{1}{20} =\sqrt[20]{6}

nikklg [1K]3 years ago
7 0
Simplified form would be twentieth root of 6

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Trigonometry<br> Special Right Triangles<br> Find the exact value of sec 60* - cosec 30* - sin 0*.
evablogger [386]

Answer:

0

Step-by-step explanation:

cos(60) = ½

sec(60) = 2

sin(30) = ½

cosec(30) = 2

sin(0) = 0

2 - 2 - 0 = 0

8 0
3 years ago
this ones pretty easy! I'm just too lazy to figure it out, whats 1/2 multiplied by 3 and 1 3/4 multiplied by 3?
galina1969 [7]

Answer:

1. 1 1/2

2. 5 1/4

Step-by-step explanation:


6 0
3 years ago
Read 2 more answers
A student wanted to construct a 95% confidence interval for the mean age of students in her statistics class. She randomly selec
VMariaS [17]

Answer:

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=19.1 represent the sample mean

\mu population mean (variable of interest)

s=1.5 represent the sample standard deviation

n=9 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=9-1=8

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,8)".And we see that t_{\alpha/2}=

Now we have everything in order to replace into formula (1):

19.1-3.355\frac{1.5}{\sqrt{9}}=17.42    

19.1+3.355\frac{1.5}{\sqrt{9}}=20.78    

And the best option would be:

C. [17.42,20.78]

5 0
3 years ago
Plz help me! It’s math!
serious [3.7K]

Answer:

The first one

Step-by-step explanation:

The number line is supposed to show the product of 2 and five, the arrow will start at 0 because 5 times 0 is 0 then it will go to 5 because 5 times 1 is 5, then another arrow will start at 5 and point at 10 because 5 times 2 is 10

The second option points backwards which would be if you were dividing 10 by 5

The third option starts at negative 10 so it shows -10 divided by -5

the last option starts at 0 and goes to -10 so it shows -5 multiplied by 2

7 0
3 years ago
Read 2 more answers
Does anyone know how to solve this?
KATRIN_1 [288]

Answer:

<30,-20>

Step-by-step explanation:

4u + 2v

4< 6,-4> + 2< 3,-2>

<24,-16> + < 6,-4>

<30,-20>

4 0
2 years ago
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