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adell [148]
3 years ago
10

Simplify fourth root of 6 over fifth root of 6.

Mathematics
2 answers:
grigory [225]3 years ago
8 0

Answer:

\sqrt[20]{6}

Step-by-step explanation:

we need to simplify

\frac{\sqrt[4]{5}}{\sqrt[5]{6}}

Each radical can be written in fraction form

\sqrt[4]{6} = 6^{\frac{1}{4}}

\sqrt[5]{6} = 6^{\frac{1}{5}}

\frac{\sqrt[4]{5}}{\sqrt[5]{6}}=\frac{6^{\frac{1}{4}}}{6^{\frac{1}{5}}}

Both top and bottom have same base so we subtract the exponents

6^{\frac{1}{4} -\frac{1}{5}}

Take common denominator to subtract the fractions

\frac{1*5}{4*5} -\frac{1*4}{5*4}

\frac{5-4}{20} =\frac{1}{20}

6^{\frac{1}{4} -\frac{1}{5}}=6^\frac{1}{20}

6^\frac{1}{20} =\sqrt[20]{6}

nikklg [1K]3 years ago
7 0
Simplified form would be twentieth root of 6

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