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adell [148]
3 years ago
10

Simplify fourth root of 6 over fifth root of 6.

Mathematics
2 answers:
grigory [225]3 years ago
8 0

Answer:

\sqrt[20]{6}

Step-by-step explanation:

we need to simplify

\frac{\sqrt[4]{5}}{\sqrt[5]{6}}

Each radical can be written in fraction form

\sqrt[4]{6} = 6^{\frac{1}{4}}

\sqrt[5]{6} = 6^{\frac{1}{5}}

\frac{\sqrt[4]{5}}{\sqrt[5]{6}}=\frac{6^{\frac{1}{4}}}{6^{\frac{1}{5}}}

Both top and bottom have same base so we subtract the exponents

6^{\frac{1}{4} -\frac{1}{5}}

Take common denominator to subtract the fractions

\frac{1*5}{4*5} -\frac{1*4}{5*4}

\frac{5-4}{20} =\frac{1}{20}

6^{\frac{1}{4} -\frac{1}{5}}=6^\frac{1}{20}

6^\frac{1}{20} =\sqrt[20]{6}

nikklg [1K]3 years ago
7 0
Simplified form would be twentieth root of 6

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Write the slope-intercept form of the equation of the line given the
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Step-by-step explanation:

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5 0
3 years ago
Knife is 3 times cost of spoon<br> 9 spoons and 12 knifes is £82.80<br> what is 1 knife
xenn [34]

Answer:

The cost of spoon is £1.84 and therefore the cost of one knife is £5.52.

Given :

  • A knife is 3 times the cost of the spoon.
  • 9 spoons and 12 knives costs £82.80.

Solution :

  • This question is solve by creating a linear equation and linear equations are nothing but yet another subset of "equations".
  • Linear calculations that requires more than one variable can be done with the help of linear equations.
  • The standard form of a linear equation in one variable is ax + b = 0.

Now let x be the cost of spoon. Than the cost knife is 3x. It is given that 9 spoons and 12 knives costs £82.80.

<h3>9x + 12 x (3x) = 82.809x + 36x = 82.8045x = 82.80x = 1.84</h3>

Therefore the cost of 1 knife = 5.52

Step-by-step explanation:  1.84 x 3 = 5.52

3 0
2 years ago
Part A Assume the ball passes through the points ( 3 , 8 ) , ( 5 , 20 3 ) , and ( 6 , 5 ) . Use this data to set up a system of
Zepler [3.9K]

The three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

<h3>What is a solution to a system of equations? (SOLUTION GRAPHICALLY)</h3>

For a solution to be the solution to a system, it must satisfy all the equations of that system, and like all points satisfying an equation are in their graphs, so solution to a system is the intersection of all its equation at a single point(as we need a common point, which is going to be the intersection of course)(this can be one or many, or sometimes none).

The general equation of parabola is given as,

y = ax² + bx + c

The first point is (3,8), therefore, we can write,

8 = a(3)² + b(3) + c

9a + 3b + c = 8

The second point is (5, 20/3), therefore, we can write,

20/3 = a(5)² + b(5) + c

75a + 15b + 3c = 20

The third point is (6, 5), therefore, we can write,

5 = a(6)² + b(6) + c

36a + 6b + c = 5

Hence, the three system of equations are 9a + 3b + c = 8, 75a + 15b + 3c = 20, and 36a + 6b + c = 5.

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6 0
2 years ago
What is the radius of a circle given by the equation x2 + y2 – 2x + 8y – 47= 0? radius = units
il63 [147K]
ANSWER

The radius is 8

EXPLANATION

We were given,

{x}^{2}  +  {y}^{2}  - 2x + 8y - 47 = 0




We rewrite the above equation to obtain,

{x}^{2}  - 2x \:  \:  \:  \:  +  {y}^{2}  + 8y \:  \:  \:  \:  = 47


We now add half the square of the coefficient of
x \: and \: y
to both sides of the equation to get,


{x}^{2}  - 2x  + ( - 1) ^{2}  +  {y}^{2}  + 8y  +  {(4)}^{2} = 47 + ( - 1) ^{2}  +   {4}^{2}



We now got two perfect squares on the left hand side of the equation,


(x - 1)^{2}   +  {(y + 4)}^{2} = 47 + 1 +   16


(x - 1)^{2}   +  {(y + 4)}^{2} =64



(x - 1)^{2}   +  {(y + 4)}^{2}  =  {8}^{2}



By comparing to the general formula of the circle,


{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}


We can see that the radius is 8.
4 0
3 years ago
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