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2 years ago

Factor 56x+32y–72z. Write your answer as a product with a whole number greater than 1.

Mathematics

1 answer:

aliina [53]2 years ago

4 0

56x + 32y - 72z

You can take out an 8 from everything.

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Four more than the quotient of a number and 3 is 9

barxatty [35]

The algebraic expression of "Four more than the quotient of a number and 3 is 9" is $\frac{x}{3}+4=9$

The value of x=15

Step-by-step explanation:

We need to express "Four more than the quotient of a number and 3 is 9" as algebraic expression.

Let the number = x

Solving:

quotient of a number and 3: $\frac{x}{3}$

Four more than the quotient of a number and 3: $\frac{x}{3}+4$

Four more than the quotient of a number and 3 is 9: $\frac{x}{3}+4=9$

Now, finding value of x:

$\frac{x}{3}+4=9\\Adding\,\,-4\,\,on\,\,both\,\,sides:\\\frac{x}{3}+4-4=9-4\\\frac{x}{3}=5\\Multiply\,\,both\,\,sides\,\,by\,\,3:\\x=5*3\\x=15$

So, value of x = 15

Keywords: Algebraic expression

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4 0

2 years ago

Find the missing side of each triangle. Round your answers to the nearest tenth if necessary.

Aneli [31]

Answer:

9 miles

Step-by-step explanation:

use Pythagoras theorem

15 squared - 12 squared = 81

square root of 81 is 9

6 0

2 years ago

Read 2 more answers

Which proportion would you use to solve this problem?

erastovalidia [21]

Answer: 225

Step-by-step explanation:

225x0.04 is 9

4 0

2 years ago

The sum of the components of anything equals the whole thing. Which property/postulate does this statement represent?

IgorC [24]

The property that is being described in the statement "The sum of the components of anything equals the whole thing" would be the Partition Postulate. It is simply the whole is equal to the sum of its parts. For instance we have a line where it contains points W, X, Y and Z, then WX + XY + YZ = WZ.

5 0

2 years ago

You invest $300 at 4% interest, compounded every year. What will your balance be after 5 years? (Remember, the formula is A = P(

Stells [14]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill\\ P=\textit{original amount deposited}\to &\$300\\ r=rate\to 4\%\to \frac{4}{100}\to &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{every year, once} \end{array}\to &1\\ t=years\to &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5\implies A\approx 364.996$

3 0

2 years ago