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prohojiy [21]
3 years ago
10

For a wedding the bride must select 4 bridesmaids from her 6 closest friends and must arrange them in order for the ceremony. Ho

w many arrangements of 4 bridesmaids from her 6 closest friends ?
A. 24
B. 360
C. 750
D. 1296
Mathematics
2 answers:
Alex3 years ago
5 0
The awnsers : A:24
Because she wouldn’t invite
360 or 750 or 1296 people plus 6•4=24
LekaFEV [45]3 years ago
5 0

Answer:

the answer is B

Step-by-step explanation:

you multiply 6,5,4,3,2,1 then divide it by 2 times 1.

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Number six on the page
Mekhanik [1.2K]
A square has the same length on all of it's sides. The area of a square is side times side. So it's 2.2×2.2=?
7 0
3 years ago
An 8-foot roll of wrapping paper costs $12.48. What is the price per inch?
Kisachek [45]

The price of this wrapping paper per inch is equal to $1,198.08.

<u>Given the following data:</u>

  • Cost of wrapping paper = $12.48.
  • Length of wrapping paper = 8 foot.

To determine the price of this wrapping paper per inch:

<h3>How to solve the problem.</h3>

In this exercise, you're required to solve for the cost of an 8-foot roll of wrapping paper that costs $12.48. Thus, we would convert the length of this wrapping paper in foot to inch and then multiply by $12.48.

<u>Conversion:</u>

1 foot = 12 inch

8 foot = X inch

Cross-multiplying, we have:

X = 8 \times 12

X = 96 inch

For price per inch:

Price = 12.48 \times 96

Price = $1,198.08

Read more on word problems here: brainly.com/question/13170908

3 0
2 years ago
Which of the following represents the zeros of f(x) = 2x3 − 5x2 − 28x + 15?
likoan [24]

\mathrm{Use\:the\:rational\:root\:theorem}

a_0=15,\:\quad a_n=2

\mathrm{The\:dividers\:of\:}a_0:\quad 1,\:3,\:5,\:15,\:\quad \mathrm{The\:dividers\:of\:}a_n:\quad 1,\:2

\mathrm{Therefore,\:check\:the\:following\:rational\:numbers:\quad }\pm \frac{1,\:3,\:5,\:15}{1,\:2}

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

-\frac{3}{1}\mathrm{\:is\:a\:root\:of\:the\:expression,\:so\:factor\:out\:}x+3

\mathrm{Compute\:}\frac{2x^3-5x^2-28x+15}{x+3}\mathrm{\:to\:get\:the\:rest\:of\:the\:eqution:\quad }2x^2-11x+5

=\left(x+3\right)\left(2x^2-11x+5\right)

Factor: 2x^2-11x+5

2x^2-11x+5=\left(2x^2-x\right)+\left(-10x+5\right)

=x\left(2x-1\right)-5\left(2x-1\right)

2x^3-5x^2-28x+15=\left(x+3\right)\left(x-5\right)\left(2x-1\right)

\left(x+3\right)\left(x-5\right)\left(2x-1\right)=0

\mathrm{Using\:the\:Zero\:Factor\:Principle:}

thus zeros of f(x) is

x=-3,\:x=5,\:x=\frac{1}{2}

5 0
3 years ago
Read 2 more answers
In a classroom of 33
amid [387]
Answer: 9 boys
Explanation:
3/11= x/33
11x= 99
x=9
5 0
3 years ago
Which is an example of a linear equation?
kobusy [5.1K]

Answer:

Step-by-step explanation:

A. (x, y)  is not an equation.

B. 2 + 7 = 9  Not a linear equation, as there is no variable.

C. 3x + 5 = 20  This is a linear equation.

D. y = 2x + 1  This is a linear equation.

5 0
3 years ago
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