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3 years ago

12z - 3 ≥ 2z - 15 it says my question is too short, so here are more characters.

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

5 0

The answer is z ≥ -6/5 :)

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Petrol costs 99p per litre. How much would 47 litres cost?

Radda [10]

Step-by-step explanation:

$99 \times 47 = 517 \times 9 = 4653$

6 0

3 years ago

Find this in the graph g(-4) =

Radda [10]

Answer:

g(-4) = 1

General Formulas and Concepts:

<u>Algebra I</u>

Reading a Cartesian plane
Coordinates (x, y)
Function Notation

Step-by-step explanation:

What g(-4) is saying is what the output of the function g(x) when x= -4. According to the graph, when x = -4, y = 1.

∴ g(-4) = 1

5 0

2 years ago

You deposit $20,000 in an account that pays 7.77% annual interest. Find the balance after 2 years when the interest is compounde

Mademuasel [1]

Answer:

The account balance after 24 months will be $23,092.70

Step-by-step explanation:

Given data

P= $20,000

r= 7.77%= 0.077

t= 2 years

A= ?

n= 24

The compound interest formula is

$A= P(1+t)^t$

Inserting our values to solve for A we have

$A= 20000(1+\frac{0.077}{24} )^2^*^2^4\\\\A= 20000(1+0.003 )^2^*^2^4\\\\A= 20000(1.003 )^2^*^2^4\\\A= 20000(1.003 )^4^8\\\A= 20000*1.15463517818\\\A= 23092.7035636\\\A= 23,092.70$

5 0

3 years ago

Solve each system of equations by graphing Y=3x+4 and y=-x-4

In-s [12.5K]

Y = 3x + 4
y = -x - 4

3x + 4 = -x - 4
3x + x = -4 - 4
4x = -8
x = -8/4
x = -2

y = 3x + 4
y = 3(-2) + 4
y = -6 + 4
y = -2

solution is (-2,-2) <==

6 0

3 years ago

A new school has x day students and y boarding students.

guapka [62]

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as $x + 2y\geq 1200$ .

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are $\$600$ a term.

So, the fees for $x$ day students are $\$600x$ a term.

The fees for a boarding student are $\$1200$ a term.

The fees for $y$ boarding student are $\$1200y$ a term.

Total fees for $x$ day students and $y$ boarding student is:

$\text{Total fees}=600x+1200y$

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

$600x+1200y\geq 720000$

$600(x+2y)\geq 720000$

Divide both sides by 600.

$\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}$

$x+2y\geq 1200$

Hence proved.

3 0

3 years ago