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vagabundo [1.1K]
2 years ago
10

What is the measure of? angle PQR [Not drawn to scale) -51 -55 -74 -78

Mathematics
2 answers:
soldi70 [24.7K]2 years ago
4 0

<u>Given</u>:

The exterior angle P is 74°

The measure of ∠PRQ is 51°

We need to determine the measure of ∠PQR

<u>Measure of ∠QPR:</u>

From the figure, it is obvious that P is the intersection of the two lines.

The angle 74° and ∠QPR are vertically opposite angles.

Since, vertically opposite angles are always equal, then the measure of ∠QPR is 74°

Thus, the measure of ∠QPR is 74°

<u>Measure of ∠PQR:</u>

The measure of ∠PQR can be determined using the triangle sum property.

Thus, we have;

\angle PQR+\angle QPR+\angle PRQ=180^{\circ}

Substituting the values, we get;

\angle PQR+74^{\circ}+51^{\circ}=180^{\circ}

       \angle PQR+125^{\circ}=180^{\circ}

                  \angle PQR=55^{\circ}

Thus, the measure of ∠PQR is 55°

Hence, Option B is the correct answer.

Monica [59]2 years ago
3 0

Answer:

Step-by-step explanation:

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bezimeni [28]

Answer:

p-q= -4

p=q-4

x^2 + px + q=0

=> x^2 + (q-4)x + q = 0

d= b^2-4ac

=(q-4)^2 - 4(1)(q)

= q^2 + 16 -8q - 4q

=q^2 -12q+16

given that D=16

q^2 -12q+16 = 16

=> q^2 -12q = 0

=> q^2 = 12q

=> q = 12q/q

=> q= 12

Therefore the value of q is 12 and the value of p is q-4 = 12-4= 8

Hope you understood............

6 0
3 years ago
Which value of x satisfies the equation sin40=cosx
svp [43]

Answer:

Try to use your calculator and just substitute values

Step-by-step explanation:

6 0
3 years ago
1.Arsenic-74 is used to locate brain tumors. It has a half-life of 17.5 days. 90 mg wereused in a procedure. Write an equation t
Sophie [7]

1)\text{   }N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) 5.625 mg will be left

Explanation:

1) Half-life = 17.5 days

initial amount of Arsenic-74 = 90 mg

To get the equation, we will use the equation of half-life:

\begin{gathered} N_t\text{ = N}_0(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}} \\ where\text{ N}_t\text{ = amount remaining} \\ N_0\text{ = initial amount} \\ t_{\frac{1}{2}\text{ }}\text{ = half-life} \end{gathered}N_t\text{ = 90\lparen}\frac{1}{2})^{\frac{t}{17.5}}

2) we need to find the remaining amount of Arsenic-74 after 70 days

t = 70

\begin{gathered} N_t=\text{ 90\lparen}\frac{1}{2})^{\frac{70}{17.5}} \\ N_t\text{ = 5.625 mg} \end{gathered}

So after 70 days, 5.625 mg will be left

4 0
1 year ago
What's the answer???????
Klio2033 [76]
Your answer is d hope this helps
8 0
2 years ago
Can someone explain to me the steps how they got 2 √4^2+2x-3-2 from this question…
Naddik [55]

Step-by-step explanation:

with your square root symbol I never know what is inside the square root and what is possibly outside.

so, I can only guess and see what comes close.

f(x) = 2x² + x - 1

g(x) = sqrt(2x - 1) ??? is that so ?

h(x) = -2

2g(f(x)) + h(x)

g(f(x)) means that the whole f(x) expression is used as x in g(x).

the whole combined function is then

2×sqrt(2(2x² + x - 1) - 1) - 2

2×sqrt(4x² + 2x - 2 - 1) - 2

2×sqrt(4x² + 2x - 3) - 2

and if I am not mistaken, then this is the solution you mentioned at the beginning (if I try to read between the typos and missing info).

this is how people get to this.

do you understand it now ? or is there still something unclear ?

6 0
2 years ago
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