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Elanso [62]
3 years ago
5

Galvanized nails are iron nails that have been plated with zinc to prevent rusting. The relevant reaction is Zn2+(aq)+2e−→Zn(s)

For a large batch of nails, a manufacturer needs to plate a total zinc mass of 3.40 kg on the surface to get adequate coverage. Part A How many moles of zinc are in 3.40 kg of zinc? Express your answer to three significant figures and include the appropriate units.
Chemistry
1 answer:
Ymorist [56]3 years ago
6 0

Answer:

52.0 moles

Explanation:

no. of moles of Zn =\frac{mass}{molar mass}=\frac{3400g}{65.38g/mol}=52.0mol

The important part in this question is changing the kilograms to grams so that the units of the mass(grams) are divisible by the units of the molar mass (grams/molar mass)

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Please explain to me how to answer no.2 questions
bulgar [2K]

Answer: -

IE 1 for X = 801

Here X is told to be in the third period.

So n = 3 for X.

For 1st ionization energy the expression is

IE1 = 13.6 x Z ^2 / n^2

Where Z =atomic number.

Thus Z =( n^2 x IE 1 / 13.6)^(1/2)

Z = ( 3^2 x 801 / 13.6 )^ (1/2)

= 23

Number of electrons = Z = 23

Nearest noble gas = Argon

Argon atomic number = 18

Number of extra electrons = 23 – 18 = 5

a) Electronic Configuration= [Ar] 3d34s2

We know that more the value of atomic radii, lower the force of attraction on the electrons by the nucleus and thus lower the first ionization energy.

So more the first ionization energy, less is the atomic radius.

X has more IE1 than Y.

b) So the atomic radius of X is lesser than that of Y.

c) After the first ionization, the atom is no longer electrically neutral. There is an extra proton in the atom.

Due to this the remaining electrons are more strongly pulled inside than before ionization. Hence after ionization, the radii of Y decreases.

4 0
4 years ago
A mixture 21.7 g NaCl 3.74 g kcl and 9.76 g licl how many moles of nacl are in this mixture
slava [35]
Moles (mol) = mass (g) / molar mass (g/mol)

Mass of NaCl = 21.7 g
Molar mass of NaCl = <span>58.4 g/mol
Hence, moles of NaCl = </span>21.7 g / 58.4 g/mol = 0.372 mol

Hence moles of NaCl in the mixture is 0.372 mol.

Let's assume that mixture has only given compounds and free of impurities.
Then, we can present this as a mole percentage.

mole % = (moles of desired substance / Total moles of the mixture) x 100%

Hence,
mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%

Total moles of mixture = moles of NaCl + KCl + LiCl

Mass of KCl = 3.74 g 
Molar mass of NaCl = 74.6 g/mol
Hence, moles of NaCl = 3.74 g  / 74.6 g/mol = 0.050 mol

Mass of NaCl = <span>9.76 g
</span>Molar mass of NaCl = 42.4 g/mol
Hence, moles of NaCl = 9.76 g / 42.4 g/mol = 0.230 mol

Total moles =  0.372 mol + 0.050 mol + 0.230 mol = 0.652 mol

mole % of NaCl = (moles of NaCl / Total moles of the mixture) x 100%
                           = (0.372 mol / 0.652 mol) x 100%
                           = 57.06% 

Hence, mixture has 57.06% of NaCl as the mole percentage.
8 0
3 years ago
What’s the force of a pitching machine on a baseball?
worty [1.4K]

Answer:

The Machine exerts a force of 9N.

Explanation:

Initial velocity (u) = 0 m/s

Final velocity (v) = 30 m/s

Time (t) = 0.5 s

Acceleration (a) = (v-u)/t

= (30-0)/0.5 m/s²

= 30/0.5 m/s²

= 60 m/s²

Mass = 0.15 kg

Force = Mass*Acceleration

= 0.15*60 N

= 9 N

7 0
2 years ago
Chloral hydrate (C2H3Cl3O2) is a drug formerly used as a sedative and hypnotic.
Dmitrij [34]

Answer :

(a) The molar mass of C_2H_3Cl_3O_2 is, 165.5 g/mole

(b) The moles of C_2H_3Cl_3O_2 is, 3.02 moles

(c) The mass in grams of 2.0\times 10^{-2} mole chloral hydrate is, 3.31 g

(d) The number of chlorine atoms in 5.0 g chloral hydrate is, 5.4\times 10^{22}

(e) The mass of chloral hydrate will be, 1.55 g

(f) The mass of exactly 500 molecules of chloral hydrate is, 1.99\times 10^{23}

Explanation :

(a) To calculate the molar mass of chloral hydrate.

The formula of chloral hydrate is, C_2H_3Cl_3O_2

Atomic mass of carbon = 12 g/mole

Atomic mass of hydrogen = 1 g/mole

Atomic mass of oxygen = 16 g/mole

Atomic mass of chlorine = 35.5 g/mole

Now we have to determine the molar mass of chloral hydrate.

\text{Molar mass of }C_2H_3Cl_3O_2=2(12g/mole)+3(1g/mole)+3(35.5g/mole)+2(16g/mole)=165.5g/mole[/tex]

The molar mass of C_2H_3Cl_3O_2 is, 165.5 g/mole

(b) Now we have to determine the moles of C_2H_3Cl_3O_2.

\text{Moles of }C_2H_3Cl_3O_2=\frac{\text{Mass of }C_2H_3Cl_3O_2}{\text{Molar mass of }C_2H_3Cl_3O_2}=\frac{500.0g}{165.5g/mole}=3.02moles

The moles of C_2H_3Cl_3O_2 is, 3.02 moles

(c) Now we have to determine the mass in grams of 2.0\times 10^{-2} mole chloral hydrate.

\text{Mass of }C_2H_3Cl_3O_2=\text{Moles of }C_2H_3Cl_3O_2\times \text{Molar mass of }C_2H_3Cl_3O_2

\text{Mass of }C_2H_3Cl_3O_2=(2.0\times 10^{-2}mole)\times (165.5g/mole)=3.31g

The mass in grams of 2.0\times 10^{-2} mole chloral hydrate is, 3.31 g

(d) To calculate the number of chlorine atoms are in 5.0 g chloral hydrate.

First we have to determine the moles of C_2H_3Cl_3O_2.

\text{Moles of }C_2H_3Cl_3O_2=\frac{\text{Mass of }C_2H_3Cl_3O_2}{\text{Molar mass of }C_2H_3Cl_3O_2}=\frac{5g}{165.5g/mole}=0.03moles

Now we have to calculate the number of chlorine atoms in chloral hydrate.

In C_2H_3Cl_3O_2, there are, 2 carbon atoms, 3 hydrogen atoms, 3 chlorine atoms and 2 oxygen atoms.

As, 1 mole of C_2H_3Cl_3O_2 contains 3\times 6.022\times 10^{23} chlorine atoms

So, 0.03 mole of C_2H_3Cl_3O_2 contains 0.03\times 3\times 6.022\times 10^{23}=5.4\times 10^{22} chlorine atoms

The number of chlorine atoms in 5.0 g chloral hydrate is, 5.4\times 10^{22}

(e) To calculate the mass of chloral hydrate would contain 1.0 g Cl.

As, 3\times 35.5g of chlorine present in 165.5 g of C_2H_3Cl_3O_2

So, 1 g of chlorine present in \frac{165.5}{3\times 35.5}=1.55g of C_2H_3Cl_3O_2

The mass of chloral hydrate will be, 1.55 g

(f) To calculate the mass of exactly 500 molecules of chloral hydrate.

As, 6.022\times 10^{23} molecules of chloral hydrate has 165.5 g mass of chloral hydrate

So, 500 molecules of chloral hydrate has \frac{6.022\times 10^{23}}{500}\times 165.5=1.99\times 10^{23} mass of chloral hydrate

The mass of exactly 500 molecules of chloral hydrate is, 1.99\times 10^{23}

3 0
3 years ago
Do you no the 5 major dairy groups​
SOVA2 [1]

I can only think of four and i dont even know if these are correct but milk, cheese, ice cream, and yogurt sorry if i'm incorrect

4 0
3 years ago
Read 2 more answers
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