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4 years ago

How many moles of propane (C3H8) are in a 7.00-L tank at 20.0°C and 5.45 atm of pressure?

1 answer:

6 0

Hey there!:

Temperature in kelvin :

20.0ºC + 273 => 293 K

R = 0.082

Volume =7.00 L

Pressure = 5.45 atm

Number of moles = ??

Therefe:

P * V = n * R * T

5.45 * 7.00 = n * 0.082 * 293

38.15 = n * 24,026

n = 38.15 / 24.026

n = 1.587 moles of propane ( C3H8 )

hope this helps!

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At a certain temperature, the decomposition of NO2 is second order with a rate constant of 2.85 M-1min-1. If one starts with 1.7

alex41 [277]

Answer: It will take 0.50 minutes for it to decompose to 28.2% of its initial value

Explanation:

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$

a= concentration left after time t = $\frac{28.2}{100}\times 1.77=0.50M$

k = rate constant = $2.85M^{-1}min^{-1}$

${a_0}$ = initial concentration = 1.77

t= time taken for decomposition

$\frac{1}{0.50}=2.85\times t+\frac{1}{1.77}$

$t=0.50min$

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3 years ago

PH of 6.7X10^-4 of H2SO4

mezya [45]

Assuming 6.7x10^-4 is in units of molarity, simply do -log(M)=pH. Substitute and get -log(6.7x10^-4) and when solving you find 3.17 is the pH

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3 years ago

A certain substance x decomposes. it is found that 50% of x remains after 100 minutes. how much x remains after 200 minutes if t

fiasKO [112]

The time needed for a substance becomes half of it mass is called half-time, after. In this case, the half time is 100 minutes. Then to know how much substance remain after 200 minutes the equation would be:

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4 years ago

Which statement describes the light reaction of photosynthesis?

cupoosta [38]

Answer:

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3 years ago

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stich3 [128]

Answer:

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Explanation:

Redox reaction with states of species:

$14H^{+}(aq.)+Cr_{2}O_{7}^{2-}(aq.)+6Cl^{-}(aq.)\rightarrow 2Cr^{3+}(aq.)+3Cl_{2}(g)+7H_{2}O(l)$

Reaction quotient for this redox reaction:

$Q_{p}=\frac{[Cr^{3+}]^{2}.P_{Cl_{2}}^{3}}{[H^{+}]^{14}.[Cr_{2}O_{7}^{2-}].[Cl^{-}]^{6}}$

Species inside third braket represent concentration in molarity, P represent pressure in atm and concentration of $H_{2}O$ is taken as 1 due to the fact that $H_{2}O$ is a pure liquid.

$pH=-log[H^{+}]$

So, $[H^{+}]=10^{-pH}$

Plug in all the given values in the equation of $Q_{p}$ :

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3 years ago