Answer:
No, the magnitude of the magnetic field won't change.
Explanation:
The magnetic field produced by a wire with a constant current is circular and its flow is given by the right-hand rule. Since this field is circular with center on the wire the magnitude of the magnetic field around the wire will be given by B = [(\mi_0)*I]/(2\pi*r) where (\mi_0) is a constant, I is the current that goes through the conductor and r is the distance from the wire. If the field sensor will move around the wire with a fixed radius the distance from the wire won't change so the magnitude of the field won't change.
Red dwarf stars evolve very differently than other stars as they age because <u>their </u><u>interiors </u><u>are well mixed, through strong convection.</u>
<h3>
What are red dwarf stars?</h3>
Red dwarf stars are the smallest and coolest kind of stars on the main sequence.
Red dwarf stars (stars between 0.08 and 0.5 solar masses) evolve very differently than other stars as they age because <u>their </u><u>interiors </u><u>are well mixed, through strong convection.</u>
Learn more about Red dwarf stars here: brainly.com/question/3151458
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Answer:
Through passive transport
Explanation:
<em>Passive transport is the movement of molecules and ions across the cell membrane whith no use of energy,</em> it usuale involves a difussion down its concentration gradient (a region where concentration changes) across a membrane, from higher to lower concentrations. Passive transport can happen by simple diffusion, facilitated diffusion, filtration, or osmosis.
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Let's call a the acceleration of the system. The problem says that the block m3 is static, so the acceleration is zero: a=0.
Calling

the tension of the string between m1 and m3, and

the tension of the string between m2 and m3, the problem can be solved by writing the following system of equations:



However, we know that a=0 and the problem asks only for

, so we just need to solve the first equation:

and so
Answer:



Explanation:
Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.
So we first find the equivalent resistance for the two resistors in parallel:

By knowing this, we can estimate the total current through the circuit,:

So approximately 0.17 amps
and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:

So now we know that the potential drop across the parellel resistors must be:
10 V - 4.28 V = 5.72 V
and with this info, we can calculate the current through R1 using Ohm's Law:
