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Karo-lina-s [1.5K]
1 year ago
13

Find the rate constantrif the population doubles in 12 days.b.ifp= 200 initially (whent= 0), what is the population whent= 18 da

ys?
Physics
1 answer:
frez [133]1 year ago
5 0

The rate constant is 0.058/days and the population after 18 days is 412.38.

<h3>What is rate constant?</h3>

The rate constant of the population is calculated as follows;

N = N₀(2)^(rt)

where;

  • r is the rate constant
  • t of double of the population

when the population doubles, t = 12 days

2N₀ = N₀(2)^(12r)

2 = (2)^(12r)

ln(2) = 12r

r = ln(2)/12

r = 0.058/days

<h3>Population size after 18 days</h3>

The population size after 18 days is calculated as follows;

N = 200(2)^(0.058 x 18)

N = 412.38

Thus, the rate constant is 0.058/days and the population after 18 days is 412.38.

Learn more about  rate constant here: brainly.com/question/11272059

#SPJ1

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4 0
2 years ago
Two objects are moving at equal speed along a level, frictionless surface. the second object has twice the mass of the first obj
Zarrin [17]

first object gors highest

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2 years ago
What are two examples of goods and two examples of services
julsineya [31]

The goods and the services make up the basis of every economy. The goods can simply be defined as merchandise or possessions. The services can be defined as the actions through which help is provided, or work is done for someone else. Example of goods are the food and furniture, with the food being crucial for the survival of the people, while the furniture is an essential part of every home and its practicality and decor. Examples of services are teaching and car repairing. The teaching is crucial for the development of the societies, as through it the people get education, while the repairing of cars is very important as lot of people have them, can not afford to buy new ones all the time, and they need for their daily movement over longer distances.

8 0
3 years ago
Two rigid tanks of equal size and shape are filled with different gases. The tank on the left contains oxygen, and the tank on t
fredd [130]

Answer:

The number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.

Explanation:

Given:

Molar mass of oxygen, M_O=32

Molar mass of hydrogen, M_H=2

We know ideal gas law as:

PV=nRT

where:

P = pressure of the gas

V = volume of the gas

n= no. of moles of the gas molecules

R = universal gs constant

T = temperature of the gas

∵n=\frac{m}{M}

where:

m = mass of gas in grams

M = molecular mass of the gas

∴Eq. (1) can be written as:

PV=\frac{m}{M}.RT

P=\frac{m}{V}.\frac{RT}{M}

        as: \frac{m}{V}=\rho\ (\rm density)

So,

P=\rho.\frac{RT}{M}

Now, according to given we have T,P,R same for both the gases.

P_O=P_H

\rho_O.\frac{RT}{M_O}=\rho_H.\frac{RT}{M_H}

\Rightarrow \frac{\rho_O}{32}=\frac{\rho_H}{2}

\rho_O=16\rho_H

∴The molecules of oxygen are more densely packed than the molecules of hydrogen in the same volume at the same temperature and pressure. So, <em>the number of oxygen molecules in the left container greater than the number of hydrogen molecules in the right container.</em>

5 0
2 years ago
An air-filled pipe is found to have successive harmonics at 700 Hz , 900 Hz , and 1100 Hz . It is unknown whether harmonics belo
Artyom0805 [142]

Answer:

the length of the pipe is 0.85 m or 85 cm

Explanation:

Given the data in the question;

The successive harmonics are;  700 Hz , 900 Hz , and 1100 H

Now, for a closed pipe,

length of pipe (L) = λ/4

Harmonics; 1x, 3x, 5x, 7x, 9x, 11x

1100Hz - 900Hz = 200Hz

⇒ 2x = 200Hz

x = 100Hz ( fundamental frequency )

λ = V/f = 340 /100 = 3.4 m

Now

Length L = λ / 4

L = 3.4 / 4

L = 0.85 m or 85 cm

Therefore, the length of the pipe is 0.85 m or 85 cm

7 0
3 years ago
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