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Karo-lina-s [1.5K]

1 year ago

13

Find the rate constantrif the population doubles in 12 days.b.ifp= 200 initially (whent= 0), what is the population whent= 18 da

ys?

1 answer:

frez [133]1 year ago

5 0

The rate constant is 0.058/days and the population after 18 days is 412.38.

<h3>What is rate constant?</h3>

The rate constant of the population is calculated as follows;

N = N₀(2)^(rt)

where;

r is the rate constant
t of double of the population

when the population doubles, t = 12 days

2N₀ = N₀(2)^(12r)

2 = (2)^(12r)

ln(2) = 12r

r = ln(2)/12

r = 0.058/days

<h3>Population size after 18 days</h3>

The population size after 18 days is calculated as follows;

N = 200(2)^(0.058 x 18)

N = 412.38

Thus, the rate constant is 0.058/days and the population after 18 days is 412.38.

Learn more about rate constant here: brainly.com/question/11272059

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Explanation:

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Using formula

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==> 37.6= 0 + 0.5 ×9.8× $t^{2}$

==> $t^{2}$ = $\frac{37.6}{4.9}$

==> t = 2.8 sec

In this time the diver has to cover a horizontal distance of 12.12 m

If x = 12.12 m is the horizontal distance to be covered then using

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3 years ago

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Answer:

c. Was an idea created and supported by Congress.

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3 years ago

What is a measure of the amount of matter in an object? Question 2 options: Force Inertia Mass Acceleration

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The electric field in a region of space increases from 0 to 2150 N/C in 5.00 s. What is the magnitude of the induced magnetic fi

Feliz [49]

To solve this problem we will use the Ampere-Maxwell law, which describes the magnetic fields that result from a transmitter wire or loop in electromagnetic surveys. According to Ampere-Maxwell law:

$\oint \vec{B}\vec{dl} = \mu_0 \epsilon_0 \frac{d\Phi_E}{dt}$

Where,

B= Magnetic Field

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$\mu_0$ = Vacuum permeability

$\epsilon_0$ = Vacuum permittivity

Since the change in length (dl) by which the magnetic field moves is equivalent to the perimeter of the circumference and that the electric flow is the rate of change of the electric field by the area, we have to

$B(2\pi r) = \mu_0 \epsilon_0 \frac{d(EA)}{dt}$

Recall that the speed of light is equivalent to

$c^2 = \frac{1}{\mu_0 \epsilon_0}$

Then replacing,

$B(2\pi r) = \frac{1}{C^2} (\pi r^2) \frac{d(E)}{dt}$

$B = \frac{r}{2C^2} \frac{dE}{dt}$

Our values are given as

$dE = 2150N/C$

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Replacing we have,

$B = \frac{r}{2C^2} \frac{dE}{dt}$

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2 years ago

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Answer:

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$F=2.84*10^{-26}N$ & +y direction

Explanation:

From the question we are told that:

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Earths magnetic field $B_e=3.04 * 10^-^8$ +z direction

a)

Generally the equation for magnetic force $F_m$ is mathematically given by

$F=q(V_e*B_e)$

where

$q=1.6*10^{-19}c\\\=i*\=z=-\=j$

$F=1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)$

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Magnitude & Direction

$F=2.84*10^{-26}N$ -y direction

b)

Generally the equation for magnitude and direction of the magnetic force on an electron. is mathematically given by

$\=F'=-1.6*10^{-19}(3.83 * 10^5 m/s*3.04 * 10^-^8)$

$\=F'=-2.84*10^{-26}N \=j$

Magnitude & Direction

$F=2.84*10^{-26}N$ & +y direction

5 0

3 years ago