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Karo-lina-s [1.5K]
1 year ago
13

Find the rate constantrif the population doubles in 12 days.b.ifp= 200 initially (whent= 0), what is the population whent= 18 da

ys?
Physics
1 answer:
frez [133]1 year ago
5 0

The rate constant is 0.058/days and the population after 18 days is 412.38.

<h3>What is rate constant?</h3>

The rate constant of the population is calculated as follows;

N = N₀(2)^(rt)

where;

  • r is the rate constant
  • t of double of the population

when the population doubles, t = 12 days

2N₀ = N₀(2)^(12r)

2 = (2)^(12r)

ln(2) = 12r

r = ln(2)/12

r = 0.058/days

<h3>Population size after 18 days</h3>

The population size after 18 days is calculated as follows;

N = 200(2)^(0.058 x 18)

N = 412.38

Thus, the rate constant is 0.058/days and the population after 18 days is 412.38.

Learn more about  rate constant here: brainly.com/question/11272059

#SPJ1

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<h3>How to calculate the speed of the electron?</h3>

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