Answer:
the required frequency of waves is 2.066 Hz
Explanation:
Given the data in the question;
μ = 1.50 kg/m
T = 6000 N
Amplitude A = 0.500 m
P = 2.00 kW = 2000 W
we know that, the average power transmit through the rope can be expressed as;
p =
vμω²A²
p =
√(T/μ)μω²A²
so we solve for ω
ω² = 2P / √(T/μ)μA²
we substitute
ω² = 2(2000) / √(6000/1.5)(1.5)(0.500)²
ω² = 4000 / 23.71708
ω² = 168.65
(2πf)² = ω²
so
(2πf)² = 168.65
4π²f² = 168.65
f² = 168.65 / 4π²
f² = 4.27195
f = √4.27195
f = 2.066 Hz
Therefore, the required frequency of waves is 2.066 Hz
Answer:
- The formula its

- After 5 years, the computer value its $ 1056
Explanation:
<h3>
Obtaining the formula</h3>
We wish to find a formula that
- Starts at 2816.

- Reach 0 at 8 years.

- Depreciates at a constant rate. m
We can cover all this requisites with a straight-line equation. (an straigh-line its the only curve that has a constant rate of change) :
,
where m its the slope of the line and b give the place where the line intercepts the <em>y</em> axis.
So, we can use this formula with the data from our problem. For the first condition:


So, b = $ 2816.
Now, for the second condition:





So, our formula, finally, its:

<h3>After 5 years</h3>
Now, we just use <em>t = 5 years</em> in our formula



Answer: 3.9 MW
Explanation:
1 W = 1 J/s
260000 J/s (15 s) = 3,900,000 = 3.9 MW
Answer:
196.34 °F
Explanation:
To convert from degrees celsius to degrees fahrenheit, use this equation:
(°C * 9/5) + 32 = °F
So, using this equation:
(91.30 * 9/5) + 32 = °F
196.34 + 32 = °F
°F = 196.34
Hope this helps!