<span>Lets call F the friction force which will act horizontally backwards.
As you are travelling at a constant velosity horizontally there is no overall resultant force in this direction.
ie. the force you pull with will be equal to the friction force resisting you. (you will initially have to have pulled with a greater force than the friction to get the suitcase moving)
the value of your force pulling is 60 cos26.9 (horizontally) - you should have learnt about resolving forces.
this must be equal to F
so
F=60cos26.9
F=53.5N
hope this helps you
please mark this as brainliest answer</span>
D.N(Newton) this is the S.I unit for force
Answer:
D) Some of the light passes through, and some of the light is absorbed or scattered by the object.
Explanation:
When light strikes translucent materials, only some of the light passes through them. The light does not pass directly through the materials. ... When light strikes an opaque object none of it passes through. Most of the light is either reflected by the object or absorbed and converted to heat.
(I googled it) ☺
Answer:
-54.12 V
Explanation:
The work done by this force is equal to the difference between the final value and the initial value of the energy. Since the charge starts from the rest its initial kinetic energy is zero.
The change in electrostatic potential energy 
, of one point charge q is defined as the product of the charge and the potential difference.
Answer:
R = 715.4 N
L = 166.6 N
Explanation:
ASSUME the painter is standing right of center
Let L be the left rope tension
Let R be the right rope tension
Sum moments about the left end to zero. Assume CCW moment is positive
R[5] - 20(9.8)[5/2] - 70(9.8)[5/2 + 2] = 0
R = 715.4 N
Sum moments about the right end to zero
20(9.8)[5/2] + 70(9.8)[5/2 - 2] - L[5] = 0
L = 166.6 N
We can verify by summing vertical forces
116.6 + 715.4 - (70 + 20)(9.8) ?=? 0
0 = 0 checks
If the assumption about which side of center the paint stood is incorrect, the only difference would be the values of L and R would be swapped.
