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I = / r where I = current and r = resistance
80 = k / 50 so
k = 400
so we have I = 400/r
when r = 40
I = 400/40 = 10 amps
Answer:
-√(1 - 2x) + C
Step-by-step explanation:
1/√(1-2x)
We want to integrate it. Thus;
∫1/√(1 - 2x) dx
Let u = 1 - 2x
Thus;
du/dx = -2
Thus, dx = -½du
Thus,we now have;
-½∫1/√(u) du
By application of power rule, we will now have;
-½∫1/√(u) du = -√(u) + C
Plugging in the value of u, we will have;
-√(1 - 2x) + C
It would be B because 64.35/7.15=9 so e=9