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Phoenix [80]
2 years ago
7

What is the simplified expression for the expression belov

Mathematics
1 answer:
11111nata11111 [884]2 years ago
6 0

Answer: 9x + 17

Step-by-step explanation: Add 4x and 5x and you get 9x. Next take away 15 from 32 and you get 17 therefore the answer wuld be 9x + 17.

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What is the solution to the system below? X=7
Olegator [25]

Answer:

A)(7,-9)

Step-by-step explanation:

we know x=7

so put it in the equation

y= -2(7)+5

y=-9

we always put the x coordinate first and then the y coordinate so the answer is (7,-9)

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3 years ago
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Svet_ta [14]

Answer:

$35 for each sweater

Step-by-step explanation:

First subtract the skirt $160 - $20 = $140

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Answer: 35

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3 years ago
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3 years ago
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90 + 12 = 6(15 + 12) Yes or No
quester [9]

Answer:

This is false.

Step-by-step explanation:

90 +  12 = 102.

6(15+12) equals to 6(27) which is 162.


8 0
3 years ago
Read 2 more answers
Determine as a linear relation in x, y, z the plane given by the vector function F(u, v) = a + u b + v c when a = 2 i − 2 j + k,
Ostrovityanka [42]

Answer:

2x - y - 3z = 0

Step-by-step explanation:

Since the set

{i, j}  = {(1,0), (0,1)}

is a base in \mathbb{R}^2

and F is linear, then

<em>{F(1,0), F(0,1)}  </em>

would be a base of the plane generated by F.

F(1,0) = a+b = (2i-2j+k)+(i+2j+k) = 3i+2k

F(0,1) = a+c = (2i-2j+k)+(2i+j+2k) = 4i-j+3k

Now, we just have to find the equation of the plane that contains the vectors 3i+2k and 4i-j+3k

We need a normal vector which is the cross product of 3i+2k and 4i-j+3k

(3i+2k)X(4i-j+3k) = 2i-j-3k

The equation of the plane whose normal vector is 2i-j-3k and contains the point (3,0,2) (the end of the vector F(1,0)) is given by

2(x-3) -1(y-0) -3(z-2) = 0

or what is the same

2x - y - 3z = 0

3 0
3 years ago
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