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3 years ago

I need help how to do Arrays and an Expanded Algorithm

1 answer:

4 0

Array:
1
1this is the Y axis
1
1
111111111111 this is the X axis
so there's a y axis and x axis.
You need to count how many dots AKA 1's are
on the x axis and y axis and multiply them.so in
this case it would be 5 times 12 so the answer would be 60.

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Halp Me i will gib brainliest

Tju [1.3M]

Answer:

Step-by-step explanation:

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3 years ago

15. For each of the following, write the probability as the intersection of two events. Then, indicate whether the two events ar

LuckyWell [14K]

Answer:

Step-by-step explanation:

a. The probability of selecting a 6 from the first draw and a 7 on the second draw when two balls are selected without replacement from a container with 10 balls numbered 1 to 10

Not independent because without replacement

Prob for both = $\frac{1}{10} \frac{1}{9} \\=\frac{1}{90}$

b. The probability of selecting a 6 on the first draw and a 7 on the second draw when two balls are selected with replacement from a container with 10 balls numbered 1 to 10

Here independent because with replacement makes probability independent.

Prob for both = P(A) *P(B) = $\frac{1}{10} *\frac{1}{10} \\=\frac{1}{100}$ d

c. The probability that two people selected at random in a shopping mall on a very busy Saturday both have a birthday in the month of June. Assume that all 365 birthdays are equally

likely, and ignore the possibility of a February 29 leap-year birthday.

Here independent because one person birthday will not affect the other person birthday

Prob for both = $(\frac{30}{365})^2\\ =\frac{25}{5329}$

d. The probability that two socks selected at random from a drawer containing 10 black socks and 6 white socks will both be black

Prob for I sock black = 10/16 and II sock black if first sock is black = 9/15

Hence not independent

Prob for both = $\frac{10C2}{16C2} \\=\frac{3}{8}$

5 0

4 years ago

Can someone help me with this please

seropon [69]

Answer: The system of equations is

40x + 55y = 920

40x + 65y = 1000

x is the cost of the adult ticket; y is the cost of the child ticket

Step-by-step explanation:

If you have to solve this, elimination is a good method.

Subtract the top equation from the second equation.

40x + 65y = 1000

<u>-40x + 55y = 920 </u> x cancels Solve for y

0 + 10y = 80 Divide both sides by 10

y = 8 . Substitute 8 for y in either equation and solve for x

40x + 65(8) = 1000

40x + 520 = 1000 Subtract 520 from both sides

40x = 1000 - 520

40x = 480 Divide both sides by 40

x = 12

4 0

3 years ago

PLEASE HELPPP!!! MEEE!!

Diano4ka-milaya [45]

the answer is the third one

4 0

3 years ago

Read 2 more answers

Rent-An-SUV charges an $80 fee to rent a truck and $12 per mile. Another rental company charges a $150 fee to rent a truck

almond37 [142]

The linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320

Since we are not told what to find, we can look for t<u>he linear equation that can be used to calculate daily car rentals</u>;

Let the charge amount be y

Let the amount per mile of the truck rent be x.

If rent-An-SUV charges an $80 fee to rent a truck and $12 per mile, this can be expressed in coordinate form as (12, 80)

Similarly, if another rental company charges a $150 fee to rent a truck and $8.50 per mile, this can also be written in a coordinate form as (8.50, 150)

The standard linear expression is given as f(x) = mx + b

m is the rate of change

b is the y- intercept

Get the rate of change;

$m=\frac{150-80}{8.5-12}\\m=\frac{70}{-3.5}\\m= -20\\$

Get the y-intercept;

80 = -20(12) + b

80 = -240 + b

b = 320

Get the required linear equation;

f(x) = mx + b

f(x) = -20x + 320

Hence the linear equation that can be used to calculate daily car rentals is f(x) = -20x + 320

Learn more on linear equation here: brainly.com/question/12788590

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3 years ago