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3 years ago

I need help how to do Arrays and an Expanded Algorithm

1 answer:

4 0

Array:
1
1this is the Y axis
1
1
111111111111 this is the X axis
so there's a y axis and x axis.
You need to count how many dots AKA 1's are
on the x axis and y axis and multiply them.so in
this case it would be 5 times 12 so the answer would be 60.

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3 years ago

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3 years ago

The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi

Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}$

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Now, $z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64$

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

$z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07$

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

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4 years ago

Suppose the probabilities for the letters on a spinner are known to be: p(A)=1/4 p(B)=1/3 p(C)=5/12 predict the number of times

svlad2 [7]

Answer:

You will end up on A 3 times, B 4 times, and C 5 times.

Step-by-step explanation:

Just divide 12 by each value and you get your answer.

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2 years ago

How to solve <br> 187=1/2*17(6+X)

lys-0071 [83]

The answer to 187=1/2*17(6+X) is X=16

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3 years ago