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olganol [36]
4 years ago
6

Identify each polynomial as either a monomial binomial or trinomial. Then state the degree and leading coefficient.

Mathematics
1 answer:
poizon [28]4 years ago
5 0

Answer with explanation:

  • Monomial  = Polynomial with one term.
  • Binomial   = Polynomial with two terms.
  • Trinomial   = Polynomial with  three terms.
  • Degree - highest power of variable
  • Leading coefficient - Coefficient of the variable or variables with highest power.

1)\ \  4x^5 + 2

Name = Binomial   (as it has two terms)

Degree= 5     (power of x)

Leading Coefficient = 4   (coefficient of x^5)

2)\ \  - 4x + 7x^3-11

Name = trinomial  (as it has 3 terms)

Degree = 3   (highest power of x)

Leading Coefficien= 7    ( coefficient of  x^3)

3)\ \  18x^5y^3z

Name= Monomial  (as it has 1 term)

Degree= 5+3+1= 9    [Addition of power of all variables]

Leading Coefficient = 18

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What is simpler answer to 28 over 35
Maurinko [17]
<span>To find the simplest form of a fraction, you have to find the greatest common factor (GCF). To do so, list out the factors of the numerator (28) and the denominator (35) and find the biggest common number between the two numbers.
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Factors of 28: 1, 2, 4, 7, 14, 28
<span>Factors of 35: 1, 5, 7, 35
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Out of those factors, we can see that 1 and 7 are the common factors, but 7 is the greatest which makes it our GCF. 

<span>Now we can divide the numerator and the denominator by the GCF to receive our simplest form.
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7 0
3 years ago
Given A-<br> 2 2<br> 1 3<br> what is A-¹?
devlian [24]

The inverse of matrix A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right] is A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

The given matrix is A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right]

The inverse of a matrix is given by

A^{-1} = \frac{1}{|A|} adjA                   ...(1)

Now, determinant of matrix A is

|A| = \left|\begin{array}{cc}2&2&1&3\\\end{array}\right|

= (3)(2) - (2)(1)

= 6 - 2

= 4

Now, adjoint A will be

A_{11} = 3

A_{12} = -1

A_{21} = -2

A_{22} = 2

AdjA = \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|

Now, substituting the values of |A| and AdjA in equation (1), we get

A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|        

Therefore, A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

Know more about Inverse of Matrix: -brainly.com/question/12442362

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7 0
2 years ago
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