Answer:
: c2 = a2 + b2 - 2ab cos C
c²=20²+15²-2×15×20×cos50
c²=400+225-600×0.64
c²=241
c=√241=15.5ft
Answer:
The slope is 10.
Step-by-step explanation:
30/3 = 10
50/5 = 10
70/7 = 10
90/9 = 10
The common factor is 10 which is the slope.
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
The cow will produce 520.25 in one day.
1.15 I think in an equation form I’m not sure though