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o-na [289]
3 years ago
15

List the first 5 multiples and find all the factors of 7

Mathematics
2 answers:
lubasha [3.4K]3 years ago
8 0
Factors: 1 & 7
Multiples: 7, 14, 21, 28, 35
Nutka1998 [239]3 years ago
8 0

Answer: First 5 multiples of 7: 7, 14, 21, 28 and 35

Factors of 7= 1 and 7

Step-by-step explanation:

Multiples of 7 are gotten by adding 7 to continously to 7 e.g 7 + 7= 14

14 + 7 =21, 21+7=28 and 28+7=35

or you can get it by multiplying 7 by 1, 2, 3, 4 etc

E.g 7×1=1, 7×2=14, 7×3=21, 7×4=28 and 7×5 =35

Factors : They are numbers that can duvide another number without remainder

Factors of 7 : They are all those number that can divide 7 without a remainder

Factors of 7 : 1, 7

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1/3h _____14 pages

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7 0
1 year ago
If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,
S_A_V [24]
Taking y=y(x) and differentiating both sides with respect to x yields

\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0

Solving for the first derivative, we have

\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y

Differentiating again gives

\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0

Solving for the second derivative, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}

Now, when x=1 and y=2, we have

\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63
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3 years ago
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3 0
3 years ago
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Answer:

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3 years ago
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