All categories

3 years ago

Determine the slope and y-intercept of the graph: 4x − 4y = 16

Mathematics

2 answers:

DIA [1.3K]3 years ago

8 0

Answer:

Slope=1

Y-intercept=-4

Step-by-step explanation:

y=mx+b where m is the slope and b is the y-intercept

For this equation i got y=1x-4

Ber [7]3 years ago

3 0

The answers 1.................

You might be interested in

I need help again.lol

Monica [59]

Answer:

$13\ units$

Step-by-step explanation:

One is asked to find the distance between two points on a coordinate plane. The easiest way to do so is to use the distance formula, this formula is the following:

$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2$

Where ( $(x_1,y_1)$ ) and ( $(x_2,y_2)$ ) are the points which one needs to find the distance between. In this case, these points are as follows:

$k\ (-3,5)$

$j\ (-8, -7)$

Substitute these points into the formula and solve for the distance between these points,

$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2$

$D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2$

Simplify,

$D=\sqrt{((-3)-(-8))^2+((5)-(-7))^2$

$D=\sqrt{(-3+8)^2+(5+7)^2$

$D=\sqrt{(5)^2+(12)^2$

$D=\sqrt{25+144}$

$D=\sqrt{169}$

$D=13$

8 0

2 years ago

Solve: 36x = 216 Step 1: 6x+2 = 216 Step 2: 6x+2 = 63 Step 3: x + 2 = 3 Step 4: x = 1 Hilary is solving the problem. If she made

NNADVOKAT [17]

Well the answer options are a bit confusing but the steps are 1, 2, & 3.

7 0

3 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago

The sum of the squares of two positive integers is 208. If the square of the larger number

iris [78.8K]

I need a little bit more detail in order to answer your question properly

3 0

3 years ago

KonstantinChe [14]

Answer:

2n-4

Step-by-step explanation:

it isn't actually lololololol reeeeèeee. Nah jk it is

4 0

3 years ago