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Alex
3 years ago
11

What value of y makes the statement true? -6(y+15)=-3+6

Mathematics
1 answer:
Nitella [24]3 years ago
7 0
I think Yes it is true
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The diameter of a circle is 20 meters. What is the circumference?
AlladinOne [14]

Step-by-step explanation:

C≈62.83m

Using the formulas

C=2πr

d=2r

Solving forC

C=πd=π·20≈62.83185m

5 0
2 years ago
9. Given the point (6,-8) values of the six trig function.
lozanna [386]

Answer:

Here's what I get.

Step-by-step explanation:

9. (6, -8)

The reference angle θ is in the fourth quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = 6² + (-8)² = 36 + 64 = 100

OB = √100 = 10  

\sin \theta = \dfrac{-8}{10} = -\dfrac{4}{5}\\\\\cos \theta =\dfrac{6}{10} = \dfrac{3}{5}\\\\\tan \theta = \dfrac{-8}{6} = -\dfrac{4}{3}\\\\\csc \theta = \dfrac{10}{-8} = -\dfrac{5}{4}\\\\\sec \theta = \dfrac{10}{6} = \dfrac{5}{3}\\\\\cot \theta = \dfrac{6}{-8} = -\dfrac{3}{4}

10. cot θ = -(√3)/2

The reference angle θ is in the second quadrant.

∆AOB is a right triangle.

OB² = OA² + AB² = (-√3)² + (2)² = 3 + 4 = 7

OB = √7

\sin \theta = \dfrac{2}{\sqrt{7}} = \dfrac{2\sqrt{7}}{7}\\\\\cos \theta = \dfrac{-\sqrt{3}}{\sqrt{7}} = -\dfrac{\sqrt{21}}{7}\\\\\tan \theta = \dfrac{2}{-\sqrt{3}} = -\dfrac{2\sqrt{3}}{3}\\\\\csc \theta = \dfrac{\sqrt{7}}{2} \\\\\sec \theta = \dfrac{\sqrt{7}}{-\sqrt{3}} = -\dfrac{\sqrt{21}}{3}\\\\\cot \theta = -\dfrac{\sqrt{3}}{2}

3 0
2 years ago
Simplify <br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7B4%7D%5E%7B2%7D%20%7D%7B16%7D%20" id="TexFormula1" title=" \fra
babunello [35]

Answer: <em>1</em>

Step-by-step explanation:

\dfrac{ {4}^{2} }{16}=\dfrac{16}{16} =1

7 0
3 years ago
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What is 7/10 equivalent to write the answer in fractions
Romashka [77]
7/10 is equivalent to 3.5/5 is one
8 0
2 years ago
Three more than the quotient of a number and 8 is 9
Alborosie

Answer:

48

Step-by-step explanation:

x/8+3=9

x/8=9-3

x/8=6

x=6*8

x=48

4 0
3 years ago
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