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solmaris [256]
3 years ago
7

A school district has $6,588 to spend on new chairs. If each chair is $36, how many chairs will the district be able to buy?

Mathematics
2 answers:
Alla [95]3 years ago
8 0

Answer:  183

Step-by-step explanation:

Let x be the maximum number of chairs they will be able to buy.

36x ≤ 6,588

x ≤ 183

They will be able to buy 183 chairs.

malfutka [58]3 years ago
5 0

Answer:

183 chairs

Step-by-step explanation:

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The answer is 4.69

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2.99+1.70= 4.69
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Please help ASAP!! Show all work and pick from the answer choices please :)
Olenka [21]
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3 years ago
The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
5 0
4 years ago
A 50% sucrose solution lost 255 mL by evaporation. After evaporation what is the sucrose concentration in the remaining 300 mL?
Len [333]

Answer: 92.50%

From the given problem, we can say that the total volume of the concentration is:

255\text{ mL}+300\text{ mL}=555\text{ mL}

The initial volume of the solution is 555 mL. After the evaporation, the 50% sucrose solution lost 255 mL.

To find the concentration of the remaining 300 mL, we will use the following formula:

C_1V_1=C_2V_2

Where:

C₁ = initial concentration

C₂ = final concentration

V₁ = initial volume

V₂ = final volume

From the given, we know that:

C₁ = 50% = 0.50

C₂ = ?

V₁ = 555 mL

V₂ = 300 mL

Substitute these to the formula and we will get:

\begin{gathered} C_{1}V_{1}=C_{2}V_{2} \\ (0.50)(555)=C_2(300) \\ C_2=\frac{(0.50)(555)}{(300)} \\ C_2=0.925=92.50\% \end{gathered}

Therefore, we can say that the sucrose concentration in the remaining 300mL is 92.50%

5 0
1 year ago
Help me please 7−s/2&gt;3
Alja [10]

Answer:

s < 8

Step-by-step explanation:

7−s/2>3

Subtract 7 from each side

7-7−s/2>3-7

-s/2 > -4

Multiply each side by -2.  Remember to flip the inequality since we are multiplying by a negative.

-s/2 * -2 < -4*-2

s < 8

3 0
4 years ago
Read 2 more answers
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