The answer is 4.69
11.96/4= 2.99
2.99+1.70= 4.69
Can you subtract them. 1x44=44
There u go
Yw
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
Answer: 92.50%
From the given problem, we can say that the total volume of the concentration is:

The initial volume of the solution is 555 mL. After the evaporation, the 50% sucrose solution lost 255 mL.
To find the concentration of the remaining 300 mL, we will use the following formula:

Where:
C₁ = initial concentration
C₂ = final concentration
V₁ = initial volume
V₂ = final volume
From the given, we know that:
C₁ = 50% = 0.50
C₂ = ?
V₁ = 555 mL
V₂ = 300 mL
Substitute these to the formula and we will get:

Therefore, we can say that the sucrose concentration in the remaining 300mL is 92.50%
Answer:
s < 8
Step-by-step explanation:
7−s/2>3
Subtract 7 from each side
7-7−s/2>3-7
-s/2 > -4
Multiply each side by -2. Remember to flip the inequality since we are multiplying by a negative.
-s/2 * -2 < -4*-2
s < 8