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Elena-2011 [213]
4 years ago
14

The admission fee at an amusement park is $2.00 for children and $6.80 for adults. On a certain day, 388 people entered the park

, and the admission fees collected totaled $1736. How many children and how many adults were admitted?
____number of children
____Number of adults
Mathematics
1 answer:
spin [16.1K]4 years ago
4 0

Answer: 188 children and 200 adults were admitted.

Step-by-step explanation:

Let x represent the number of children that were admitted that day.

Let y represent the number of adults that were admitted that day.

On a certain day, 388 people entered the park. It means that

x + y = 388

The admission fee at the amusement park is $2.00 for children and $6.80 for adults. The admission fees collected that day totaled $1736. It means that

2x + 6.8y = 1736- - - - - - - - - - - 1

Substituting x = 388 - y into equation 1, it becomes

2(388 - y) + 6.8y = 1736

776 - 2y + 6.8y = 1736

- 2y + 6.8y = 1736 - 776

4.8y = 960

y = 960/4.8

y = 200

x = 388 - y = 388 - 200

x = 188

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3 years ago
SOMEONE HELP ASAPPPP PLEASEEE,PLEASE EXPLAIN HOW U GOT YOUR ANSWER, I NEED AN EXPLANATION IN ORDER TO COMPLETE THIS! NO LINKS OR
slega [8]

Answer:

1)

A)

We must use the formula b x h/2  12 x 8/2 = 48    

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B)

We must use the formula 1/2a root c squared - a squared

Solving and substituing will get you 35.78

2)

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We must divide 81 by 2 to get 9. Since this is a square, all sides will be 9. Then, we must add 9 four times to get 36 cm as our perimeter

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5 0
3 years ago
Y= x^2 -5 solve for x
dexar [7]

Y= x^2 -5

We need to solve for x, we need to get x alone

Y= x^2 -5

Lets start by removing -5

Add 5 on both sides

y + 5= x^2 -5 + 5

y + 5= x^2

Now to isolate x , we need to remove the square from x

To remove square , take square root on both sides

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3 years ago
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8 0
4 years ago
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DanielleElmas [232]

Answer:

Step-by-step explanation:

Given expression is,

\text{cot}A=\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})

To prove this identity we will take the right side of the identity,

\frac{1}{2}(\text{cot}\frac{A}{2}-\text{tan}\frac{A}{2})=\frac{1}{2}(\frac{1}{\text{tan}\frac{A}{2}}-tan\frac{A}{2})

                         =\frac{1}{2}(\frac{1-\text{tan}^2\frac{A}{2}}{tan\frac{A}{2}})

                         =\frac{1}{2}[\frac{2(1-\text{tan}^2\frac{A}{2})}{2tan\frac{A}{2}}]

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Hence right side of the equation is equal to the left side of the equation.

3 0
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