Answer:

Step-by-step explanation:
Given

Required
The nth term
The given sequence is a geometric sequence.
So, first we identify the first term

Calculate common ration
or 

So, the nth term is:


The way that I would explain it is that you have 3610 and it is a whole number there basically 3 numbers so the 3 would be in the ones place 6 in the tenth and 1 in the hundredths place and your answer is 3.61 or another is .361
List of the first few prime numbers greater than 3:
5, 7, 11, 13, 17, 19, 23, 29
Now find the combination that you can multiply and still have a 2 digit number:
5 x 7 = 35
5 x 11 = 55
5 x 13 = 65
5 x 17 = 85
5 x 19 = 95
5 x 23 = 115 ( 3 digit number, can't use).
7 x 5 = 35
7 x 11 = 77
7 x 13 = 91
7 x 19 = 133 ( 3 digit number, can't use).
The largest 2 digit number would be 5 x 19 = 95
-2/5
Step by Step :
18 - 8 = 10
-15 - 10 = -25
10/-25 = -2/5