Answer:
Option A
Step-by-step explanation:
The complete question is attached here
The rate of increase of bacterial population be K
As we know

where Y is the final population. In this case it is 1000
K is the rate of increase of population i.e 3 times per hour
T is the time in hours
Y0 is the initial population = 5
Substituting the given values, we get -

Taking log on both sides, we get -
ln
= ln 

T = 2.084 hours
hence, option A is correct
Answer:
Volume: V≈113.1
Step-by-step explanation:
Solved for sphere
Shape: Sphere
Formula: V=43πr3
Volume: V≈113.1
1: R is the radius meaning calculate the radius to find the volume of a sphere.
2: The correct answer is below for this question.
Answer: V≈113.1
<em><u>Hope this helps.</u></em>
Answer:
(2,4) I hope this helps :))
Answer:
no solution
Step-by-step explanation:
There is no solution to this inconsistent system of linear equations. They describe parallel lines.
__
Adding twice the first equation to the second gives ...
2(5x +6y) +(-10x -12y) = 2(16) +(25)
0 = 57 . . . . . . . simplify. False
No values of x and y will make this statement true. There is NO SOLUTION to the system of equations.
Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width
:
- Area of triangle with base
and height
:
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of
units squared, and the both of them have a total area of
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)