First, let's add 2.75 + 0.158. First, we add the thousandths places. Now, we have 2.758 + 0.15. Next, let's add the hundredths place. This is equal to 2.808+0.1. Finally, we have the tenths place. Now, our number is 2.908.
To finish this problem, we add 0.003. 2.908 + 0.003 = 2.911, so 2.911 is the answer to this problem.
Answer:y=4/3
y is directly proportional to x^2 is written as
introducing a constant,
y=kx^2
but from the question, when y=2 , x=3 . putting it in the formula to get the value of k

2=9k . <em>divi</em><em>ding</em><em> </em><em>throu</em><em>gh</em><em> </em><em>by</em><em> </em><em>9</em><em> </em><em>to</em><em> </em><em>get</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>k</em>
<em>
</em>
<em>
</em>
<em>pu</em><em>tting</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>ge</em><em>neral</em><em> </em><em>expres</em><em>sion</em>
<em>
</em>
<em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>whe</em><em>n</em><em> </em><em>x</em><em>=</em><em>6</em>
<em>
</em>
<em>
</em>
<em>there</em><em>fore</em><em> </em><em>the</em><em> </em><em>valu</em><em>e</em><em> </em><em>of</em><em> </em><em>y</em><em> </em><em>when</em><em> </em><em>x</em><em>=</em><em>6</em><em> </em><em>is</em>
<em>4</em><em>/</em><em>3</em>
Answer:
2,583,283 cubic metres (91,227,778 cu ft)
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
see attached
Step-by-step explanation:
Each digit of the quotient is aligned with the least significant digit of the current dividend. The "current dividend" is that portion of the remaining dividend that is at least 1 and less than 10 times the divisor. The product of the quotient digit and the divisor is subtracted from the "current dividend" to get the remaining dividend.
__
For many folks, the hardest part of this algorithm is determining the appropriate quotient digit, and multiplying that by the divisor. Some teachers teach that you start this process by making a list of the multiples of the divisor:
N . . . 28N
1 28
2 56
3 84
4 112
...
This process can be aided by your number sense.
2N is simply N added to itself.
3N is N+2N.
4N is double 2N
5N is half of 10N.
You can proceed to build the table by adding 28 to each previous value, or by recognizing doubles and halves and other sums.