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2 years ago

I need help plssss ??! Anybody ?

Mathematics

1 answer:

Lina20 [59]2 years ago

4 0

Answer:

<DEF = 1/2(236 - 124)

Step-by-step explanation:

<DEF = 1/2(236 - 124)

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12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5

Gnesinka [82]

$\large\underline{\sf{Solution-}}$

Given that,

In triangle TPQ, 

RS || PQ,

RS = 3 cm,

PQ = 6 cm,

ar(∆ TRS) = 15 sq. cm

As it is given that, RS || PQ

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

$\rm\implies \: \triangle TPQ \: \sim \: \triangle TRS \: \: \: \: \: \: \{AA \}$

Now, We know 

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)} = \dfrac{ {PQ}^{2} }{ {RS}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{ {6}^{2} }{ {3}^{2} }$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = \dfrac{36 }{9}$

$\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15} = 4$

$\rm\implies \:ar( \triangle \: TPQ) = 60 \: {cm}^{2}$

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2 years ago

8 x(11-3) + 9 with and exponent of 2

lesya692 [45]

Answer:

Step-by-step explanation:

first u have to subtract 11 and 3 with is 8 and then you have to multiply 8 times 8 which is 64 aqnd then plus 9 and there u get 73

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If x-1/x=5 find x^3+1/x^3=?

ipn [44]

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Answer:

1+7=8

Step-by-step explanation:

I hope it helps

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