Answer:
(53.812 ; 58.188) ; 156
Step-by-step explanation:
Given that :
Sample size (n) = 51
Mean (m) = 56
Standard deviation (σ) = 9.5
α = 90%
Using the relation :
Confidence interval = mean ± Error
Error = Zcritical * (standard deviation / sqrt (n))
Zcritical at 90% = 1.645
Error = 1.645 * (9.5 / sqrt(51))
Error = 1.645 * 1.3302660
Error = 2.1882877
Hence,
Confidence interval :
Lower boundary = 56 - 2.1882877 = 53.8117123
Upper boundary = 56 + 2.1882877 = 58.1882877
Confidence interval = (53.812 ; 58.188)
2.)
Margin of Error (ME) = 1.25
α = 90%
Sample size = ((Zcritical * σ) / ME)^2
Zcritical at 90% = 1.645
Sample size = ((1.645 * 9.5) / 1.25)^2
Sample size = (15.6275 / 1.25)^2
Sample size = 12.502^2 = 156.3000
Sample size = 156
I don’t think there is a number that does both of those, the factors of 49 are 1, 7, and 49
Answer:
8/3
Step-by-step explanation:
i put equations as this:
x+40 = y
where x is galllons of pure mixture and y is the gallons of the new mixture
the other equation i id was:
x+0.2(40) = 0.25y
x+8 = 0.25y
y = 4x+32
solve using substitution
(x+40) = 4x+32
x = 4x-8
-3x = -8
x = 8/3
Answer:
12
Step-by-step explanation:
Mean is the average of all the numbers. Add up all the numbers then divide by how many you have.
We can use the same equation to figure out with only substituting the amount he was paid per photo.
Site A y = $0.85x = $0.85(5) = $4.25
Site B y = $0.40x = $0.40(5) = $2.00
We can see that Jim was paid $2.25 more at site A than Site B.
