The length of a rectangle is twice it’s width. The perimeter is 102 inches. Write an equation and find the length and width

Mathematics

1 answer:

Ganezh [65]3 years ago

7 0

Answers:

Equation is 2*(2*W+W) = 102

Width is 17

Length is 34

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Explanation:

L = 2*W because the length is twice the width

2*(L+W) = P is the perimeter formula

Replace P with the given perimeter (102). Also replace L with 2*W. Then isolate W

2*(L+W) = P

2*(2*W+W) = 102

2*(3W) = 102

6W = 102

6W/6 = 102/6

W = 17

If the width is W = 17, then the length is

L = 2*W = 2*17 = 34

So the width and length of this rectangle is 17 by 34

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Check:

P = 2*(L+W)

P = 2*(34+17)

P = 2*51

P = 102

Answer is confirmed

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Which expression represents the distance between the points (11, 4) and (5,8)?

antiseptic1488 [7]

Answer:

$\displaystyle d = 2\sqrt{13}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Coordinates (x, y)

Algebra II

Distance Formula: $\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step-by-step explanation:

Step 1: Define

Point (11, 4) → x₁ = 11, y₁ = 4

Point (5, 8) → x₂ = 5, y₂ = 8

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

Substitute in points [Distance Formula]: $\displaystyle d = \sqrt{(5-11)^2+(8-4)^2}$
[√Radical] (Parenthesis) Subtract: $\displaystyle d = \sqrt{(-6)^2+(4)^2}$
[√Radical] Evaluate exponents: $\displaystyle d = \sqrt{36+16}$
[√Radical] Add: $\displaystyle d = \sqrt{52}$
[√Radical] Simplify: $\displaystyle d = 2\sqrt{13}$