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mel-nik [20]
3 years ago
15

Given that 2x + 7 = 27 and 3x + 1 = 28, does 2x + 7 = 3x + 1

Mathematics
2 answers:
Ket [755]3 years ago
7 0
The answer to your selected question is no because they equal different numerical values
Sholpan [36]3 years ago
7 0
No
in the first equation x is = to 10
in the second equation x is = to 9

I got this by first subtracting 7 from 27. I got 20. then I divided 20 by 2 and got 10 for x

for the second I subracted 1 from 28 and got 27. then I divided that by 3 to get x=9
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According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?
scoundrel [369]

we have

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we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

x=\frac{p}{q}

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to 3

and the first monomial is equal to 15x^{11} -----> coefficient is 15

So

possible values of p are 1, and\ 3

possible values of q are 1, 3, 5, and\ 15

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-)\frac{1}{15},(+/-)\frac{1}{5},(+/-)\frac{1}{3},(+/-)\frac{3}{5},(+/-)1,(+/-)3


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3 years ago
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Answer:

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