Answer:
$890.4
Step-by-step explanation:
840 + .06(840)
840 + 50.4
890.4
Step-by-step explanation:
1. k = 76°
2. r = 25cm
3. as the drawing attached
one pair of parallel lines : AB and DC
one pair of equal angles : <em>L</em><em> </em>A and <em>L</em><em> </em>D
4. (7²× 3`¹)⁴×7^5 / (3² × 7^(-6))³
= (7^8 × 3`⁴)×7^5/ (3² × 7^(-6))³
= (7^13 × 3`⁴)/ (3^6 × 7^(-18))
= (7^(31) × 3^(-10))
= 7^31 / 3^10
Answer: 3.5, 4.5, 9.5, 3.5
Step-by-step explanation:
Look at the image below to see where A, B, C, and D are.
A + B = 8
B + D = 8
A + C = 13
C - D = 6
we can see that A + B = 8 and D + B = 8, so A = D
substitute this into A + C = 13 to get D + C = 13
from D + C = 13 we can get D = 13 - C
plug this into C - D = 6 to get C - (13 - C) = 6
2C - 13 = 6
2C = 19
C = 9.5
Now we can find D = 13 - C = 13 - 9.5 = 3.5
D = 3.5
Now we can find A = D = 3.5
A = 3.5
Now we can find B from A + B = 8
B = 8 - A = 8 - 4.5 = 4.5
B = 4.5
The height of the tank must be at least 1 foot, or 12 inches. We know the floor area (which is length x width) must be at least 400 inches. Therefore these minimum dimensions already tell us that the minimum volume is 400 x 12 = 4800 cubic inches. Since we have a maximum of 5000 cubic inches, the volume must be within the range of 4800 - 5000 cubic inches.
We can set the height at exactly 1 ft (or 12 inches). Then we can select length and width that multiply to 400 square inches, for example, L = 40 inches and W = 10 in. This gives us a tank of dimensions 40 x 10 x 12 = 4800 cubic inches, which fits all the criteria.