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Alisiya [41]
3 years ago
14

Rocky simplified an expression in three steps, as shown:

Mathematics
2 answers:
Allisa [31]3 years ago
7 0

Answer:

Step 3.

Step-by-step explanation:

The given expression is

(\frac{x^{-5}y^2}{yx^3\cdot x^3y^{-5}})^2

Step 1: Using distributive property of exponent we get

\frac{(x^{-5})^2(y^2)^2}{(y)^2(x^3)^2\cdot (x^3y^{-5})^2}      [\because (ab)^x=a^xb^x]

\frac{x^{-10}y^4}{y^2x^6\cdot x^6y^{-10}}

Ste 2: Using product property of exponent, we get

\frac{x^{-10}y^4}{y^{2-10}x^{6+6}}      [\because a^ma^n=a^{m+n}]

\frac{x^{-10}y^4}{y^{-8}x^{12}}

Step 3: Using quotient property of exponent, we get

x^{(-10-12)}y^{4-(-8)}      [\because \frac{a^m}{a^n}=a^{m-n}]

x^{(-22)}y^{12}

Therefore, the first incorrect step is 3.

Black_prince [1.1K]3 years ago
3 0

Answer:

Step three is wrong because when you divide use the quotient rule which is in division the exponents are subtracted and in this problem the exponents are added

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Which shows 0.23 repeated as a fraction.<br> A. 2/33 <br> B. 7/33 <br> C. 23/99 <br> D. 7/30
sergij07 [2.7K]

Answer: c

Step-by-step explanation: 23/99 as a fraction

8 0
3 years ago
How do I simplify the expression around the perimeter of the triangle?
Softa [21]

Answer:

it is either positve 13 or negative 13

Step-by-step explanation:

3 0
3 years ago
Select the equations whose graphs are parallel to the graph of the equation y=23x+5.
iren [92.7K]

Answer:

2x-3y=9    and    4x-6y=30

Step-by-step explanation:

hello :  

note y=(2/3)x+5  no y=23x+5

2/3 is the slope....... all lines parallel to this line has same slope.

1)   2x-3y=9   means : 3y = 2x-9   divide by 3 : y=(2/3)x-3..same slope.

2)  4x-6y=30  means : 6y= 4x-30 divide by 6 : y=(4/6)x -30/6

but 4/6 = 2/3 so : y=(2/3)x-5..same slope.

6 0
3 years ago
Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows
koban [17]

Answer:

The amount of Polonium-210 left in his body after 72 days is 6.937 μg.

Step-by-step explanation:

The decay rate of Polonium-210 is the following:

N(t) = N_{0}e^{-\lambda t}     (1)

Where:

N(t) is the quantity of Po-210 at time t =?

N₀ is the initial quantity of Po-210 = 10 μg

λ is the decay constant  

t is the time = 72 d  

The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.    

First, we need to find the decay constant:

\lambda = \frac{ln(2)}{t_{1/2}}    (2)

Where t(1/2) is the half-life of Po-210 = 138.376 days

By entering equation (2) into (1) we have:

N(t) = N_{0}e^{-\frac{ln(2)}{t_{1/2}}*t}} = 10* \frac{99.498}{100}*e^{-\frac{ln(2)}{138.376}*72} = 6.937 \mu g    

Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.  

I hope it helps you!  

8 0
3 years ago
I need help with this question
Murrr4er [49]

The number of cows is given by

14\cdot 2^{\frac{y}{5}}

So, after k years, the number of cows will be

14\cdot 2^{\frac{y+k}{5}}

We want this number to be twice as much as the original:

14\cdot 2^{\frac{y+k}{5}} = 2(14\cdot 2^{\frac{y}{5}})

First of all, we can cancel 14 from both sides:

2^{\frac{y+k}{5}} = 2\cdot 2^{\frac{y}{5}}

Finally, on the right hand side, we can use the exponent rule

a^b\cdot a^c=a^{b+c}

to get

2^{\frac{y+k}{5}} = 2^{\frac{y}{5}+1}

To solve this equation, we must impose that the two exponents are the same:

\dfrac{y+k}{5} = \dfrac{y}{5}+1 \iff \dfrac{y+k}{5} = \dfrac{y+5}{5}

And clearly this is true if and only if k=5. So, it will take 5 years for the cow heard to double in number.

You can do the exact same steps to find the doubling time for the sheeps.

8 0
3 years ago
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