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3 years ago

tom has twice as many marbles as luke. together they have 39 marbles. how many marbles does tom have?

2 answers:

Alex3 years ago

5 0

Tom has 26 marbles. Let x= the amount of marbles Luke has. If Tom has twice as much, the amount of marbles he has is represented as 2x. 2x+x=39. 3x=39. X=13, and since Tom has twice that amount, 13 times 2 is 26! Hope this helped! ;)

kodGreya [7K]3 years ago

3 0

Tom has 26 marbles. if you need to show your work it would be 13x2= 26 and 26+13=39

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Answer:

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Step-by-step explanation:

Given

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Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

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