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3 years ago

Is the function f(x) x³-11x odd even or neither

Mathematics

1 answer:

Paul [167]3 years ago

4 0

Answer:

Step-by-step explanation:

A function is odd if f(-x) = -f(x)

A function is even if f(-x) = f(x)

And neither if neither are true.

In this case if we plugged in a negative x here

f(-x) = (-x)^3 - 11(-x)

f(-x) = -x^3 + 11

Therefore, this function is odd because if we pulled out a negative one again we would get back the original function. Or in other words f(-x) = -f(x) for f(x) = x^3 - 11x

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What is the radius of a circle whose equation is x2 + y2 + 8x – 6y + 21 = 0?

s344n2d4d5 [400]

Answer:

2 units

Step-by-step explanation:

The given equation of the circle is:

$x^{2} + y^{2}+8x-6y+21=0$

The general equation of the circle is:

$x^{2} + y^{2}+2gx+2fy+c=0$

Comparing the given equation with the general equation we can say:

g = 4

f = -3

c = 21

The formula for radius of the circle is:

$radius=\sqrt{g^{2} +f^{2} -c }$

Using these values of the given circle, we get:

$radius=\sqrt{(4)^{2}+(-3)^{2}-21}\\\\radius=\sqrt{4}\\\\radius=2$

Therefore, the length of radius of the given circle is 2.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Is the function f(x) x³-11x odd even or neither​

Is the function f(x) x³-11x odd even or neither