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3241004551 [841]
3 years ago
5

A particular chemistry book costs $6 less than a particular physics book, while two such chemistry books and three such physics

books cost a total of $123. Construct two simultaneous equations and solve them using the substitution method.
Mathematics
1 answer:
sladkih [1.3K]3 years ago
3 0

Answer:

Step-by-step explanation:

Let's say the Physics book costs $x

The Chemistry book will cost $x - $6

Two such Chemistry books will cost;

2($x - $6) = $(2x - 12)

Three such Physics books cost $3x

$(2x - 12) + $3x = $123

$5x - $12 = $123

$5x = $111

x = $22\frac{1}{5}

So the Physics book costs;  $22\frac{1}{5}

and the Chemistry book costs  $22\frac{1}{5} - 6 =  $16\frac{1}{5}

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Step-by-step explanation:

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You roll two fair dice, one green and one red. (a) Are the outcomes on the dice independent? Yes No (b) Find P(1 on green die an
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Answer:

a

  Yes

b

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Step-by-step explanation:

From the question we are told that

     Two fair dice, one green and one red were rolled

Generally the  outcomes on the dice independent because the outcome on the first dice is not affected by the second die

Generally the  probability of getting a 1  on a dice rolled is  P(1) =  \frac{1}{6}

the  probability of getting a 5 on a dice rolled is  P(5) =  \frac{1}{6}

Generally the probability of P(1 on green die and 5 on red die) is mathematically represented as

         P(1 \& 5) = \frac{1}{6}  *\frac{1}{6}

         P(1 \& 5) = \frac{1}{36}

Generally the probability of P(5 on green die and 1 on red die) is mathematically represented as

          P(5 \& 1) = \frac{1}{6}  *\frac{1}{6}

         P(5 \& 1) = \frac{1}{36}

Generally the probability of P((1 on green die and 5 on red die) or (5 on green die and 1 on red die)) is mathematically represented as

          P(5 \& 1 | 1\& 5  ) = \frac{1}{36} + \frac{1}{36}

         P(5 \& 1 | 1\& 5  ) = \frac{1}{18}

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