Answer:
Step-by-step explanation:
its false
Answer:
a)The expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b)0.6004
c)19.607
Step-by-step explanation:
Let X denotes the number of fragments in 200 gm chocolate bar with expected number of fragments 10.2
X ~ Poisson(A) where 
a)We are supposed to find the expected number of insect fragments in 1/4 of a 200-gram chocolate bar

50 grams of bar contains expected fragments = \lambda x = 0.051 \times 50=2.55
So, the expected number of insect fragments in 1/4 of a 200-gram chocolate bar is 2.55
b) Now we are supposed to find the probability that you have to eat more than 10 grams of chocolate bar before ending your first fragment
Let X denotes the number of grams to be eaten before another fragment is detected.

c)The expected number of grams to be eaten before encountering the first fragments :
s
First subtract three from both sides. then you have

+2x=-3 and you solve from there
Answer:
a)2/7
b)41/48
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<em>Step-by-step explanation:</em>
<u>-Question A-</u>
1) Rephrase the problem to look like this:
3/7*28/15*5/14 <-- when dividing fractions you actually multiply by the reciprocal (opposite)
2) Multiply across the above phrase:
420/1470
3) Simplify your fraction:
2/7
There is nothing else to be done with 2/7 and thus it is your final answer.
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<u>-Question B-</u>
1) Get the denominator of all 3 fractions to the same Least Common Denominator (48):
42/48 + 3/48 - 4/48
2) Do the arithmetic in the phrase above:
41/48
41/48 cannot be simplified and thus is your final answer
I’m pretty sure all you have to do is plug in your numbers for example number 5 is y=2x-2 so you would plug in the first number which is -1. So the equation that you solve would be y=2 times -1 minus 2. That would be -4. I hope this helps. If you need further explanation please say so in comments.