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Kobotan [32]
3 years ago
13

A recipe for a loaf of bread calls for of a cup of flour. If Milo used 12 cups of flour, how many loaves of bread did he prepare

?
A.
18
B.
16
C.
15
D.
12
E.
8
Mathematics
2 answers:
Free_Kalibri [48]3 years ago
5 0

Answer:

D) 12 loaves

Step-by-step explanation:

aalyn [17]3 years ago
3 0
12 loaves hope you got a good grade:)
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A car rental agency rents 190 cars per day at a rate of 29 dollars per day. for each 1 dollar increase in the daily rate, 5 fewe
Leviafan [203]

The equation that we can create from this situation is:

i = (190 – 5 x) * (29 + x)

where i is the income and x is the increase in daily rate

Expanding the equation:

i = 5510 + 190x – 145x - 5x^2

i = -5x^2 + 45x + 5510

Taking the 1st derivative:

di/dx = -10x +45

Set to zero to get the maxima:

-10x + 45 = 0

x = 4.5

 

So the cars should be rented at:

29 + x = 33.5 dollars per day

 

The maximum income is:

i = (190 – 5*4.5) * (33.5)

i = 5,611.25 dollars

7 0
2 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
2 years ago
Will mark brainliest if you help!!!!!​
Katyanochek1 [597]

Answer:

.70

Step-by-step explanation:

5 and up round up so it would round to .7

3 0
3 years ago
(2x - 3y)(4x - y) can you help me
Mnenie [13.5K]

Answer:

<h2>(2x - 3y)(4x - y) = 8x² - 14xy + 3y²</h2>

Step-by-step explanation:

Use FOIL:  <em>(a + b)(c + d) = ac + ad + bc + bd</em>

(2x - 3y)(4x - y) = (2x)(4x) + (2x)(-y) + (-3y)(4x) + (-3y)(-y)

= 8x² - 2xy - 12xy + 3y²

<em>combine like terms</em>

= 8x² + (-2xy - 12xy) + 3y² = 8x² - 14xy + 3y²

3 0
3 years ago
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An animal shelter takes in an average of 5 animals per day. The shelter must keep its total occupancy below 300. Currently, the
Akimi4 [234]

Answer:

B. x<27

Step-by-step explanation:

300-165=135

135/5=27

8 0
3 years ago
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