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4 years ago

A square is shown below. Which expression can be used to find the area, in square units, of the shaded triangle in the square?

Mathematics

1 answer:

BaLLatris [955]4 years ago

4 0

We will use this formula = 1/2 × base × height

And thus

1/2 × 8 ×8

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Answer this: 15 cookies to 40 brownies as a ratio in simplest form.

Nutka1998 [239]

Solutions

⇒15 Cookie to 40 brownies can be written as 15:40

⇒15:40 is the ratio we have to simplify

The GCF of 15 and 40 is 5 so we divide them by 5

15 ÷ 5 = 3
40 ÷ 5 = 8

3:8 is in simplest form

8 0

3 years ago

Read 2 more answers

the population of the word grows exponentially at a rate of 1.1 per year. find the number of years it takes for the population t

alexgriva [62]

Answer:

8.4 you just add it so i hope it helps

6 0

3 years ago

Please solve 5q+6=2q-2+q.

son4ous [18]

Answer:

q= -4

Step-by-step explanation:

$5q + 6 = 2 q- 2 + q$

Collect like terms and simplify

$5q - 2q - q = - 2 - 6 \\ 2q = - 8$

Divide both sides of the equation by 2

$\frac{2q}{2} = \frac{ - 8}{2} \\$

Simplify

$q = - 4$

4 0

3 years ago

Read 2 more answers

A bank lent $200,500 for the development of two products. If the loan for priduct X was for $50,500 more than that for product Y

Kaylis [27]

Answer:

$75,000

Step-by-step explanation:

Let

x ----> amount lent for product X

y ---->amount lent for product Y

we know that

A bank lent $200,500 for the development of two products

$x+y=200,500$ ----> equation A

The loan for product X was for $50,500 more than that for product Y

$x=y+50,500$ ----> equation B

substitute equation B in equation A

$y+50,500+y=200,500$

solve for y

$2y=200,500-50,500\\2y=150,000\\y=\$75,000$

8 0

3 years ago

Find the 11th partial sum of the summation of negative 7i plus 22, from i equals 1 to infinity.

marta [7]

I think you mean,

$\sum_{i=1}^{\infty}(7i+22)$

You can use the usual formula,

$S_{k}=\frac{k}{2}(a_1+a_k)$

That in this case is,

$S_{11}=\frac{11}{2}(29+99)=704$

Where I have used,

$a_k=7\cdot k +22$

3 0

3 years ago