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Lunna [17]
3 years ago
10

A bank lent $200,500 for the development of two products. If the loan for priduct X was for $50,500 more than that for product Y

, how much was lent for product Y​
Mathematics
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

$75,000

Step-by-step explanation:

Let

x ----> amount lent for product X

y ---->amount lent for product Y

we know that

A bank lent $200,500 for the development of two products

so

x+y=200,500 ----> equation A

The loan for product X was for $50,500 more than that for product Y

so

x=y+50,500 ----> equation B

substitute equation B in equation A

y+50,500+y=200,500

solve for y

2y=200,500-50,500\\2y=150,000\\y=\$75,000

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klemol [59]

Answer:

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Step-by-step explanation:

The y-intercept must be at -7, so that eliminates C.

Because of the direction of the line, the slope needs to be negative. This eliminates B.

The slope of the line is -7/6, so D is the correct answer.

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Determine whether a figure with the given vertices is a rectangle using the Distance Formula.
Alex Ar [27]

Answer:

Yes; Opposite sides are congruent, and diagonals are congruent.

Step-by-step explanation:

we have

A(4, -7), B(4, -2), C(0, -2), D(0, -7)

we know that

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the length of the sides

<u><em>Find the distance AB</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(4-4)^{2}}

d=\sqrt{(5)^{2}+(0)^{2}}

AB=5\ units

<u><em>Find the distance BC</em></u>

substitute the values

d=\sqrt{(-2+2)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

BC=4\ units

<u><em>Find the distance CD</em></u>

substitute the values

d=\sqrt{(-7+2)^{2}+(0-0)^{2}}

d=\sqrt{(-5)^{2}+(0)^{2}}

CD=5\ units

<u><em>Find the distance AD</em></u>

substitute the values

d=\sqrt{(-7+7)^{2}+(0-4)^{2}}

d=\sqrt{(0)^{2}+(-4)^{2}}

AD=4\ units

Compare the length sides

AB=CD

BC=AD

therefore

Opposite sides are congruent

step 2

Find the length of the diagonals

<u><em>Find the distance AC</em></u>

substitute the values

d=\sqrt{(-2+7)^{2}+(0-4)^{2}}

d=\sqrt{(5)^{2}+(-4)^{2}}

AC=\sqrt{41}\ units

<u><em>Find the distance BD</em></u>

substitute the values

d=\sqrt{(-7+2)^{2}+(0-4)^{2}}

d=\sqrt{(-5)^{2}+(-4)^{2}}

BD=\sqrt{41}\ units

Compare the length of the diagonals

AC=BD

therefore

Diagonals are congruent

The figure is a rectangle, because Opposite sides are congruent, and diagonals are congruent

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