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3 years ago

How can I solve 30x-18-5-4x=55

1 answer:

3 0

$\text{Solver for x:}\\\\30x-18-5-4x=55\\\\\text{Combine like terms}\\\\26x-18-5=55\\\\26x-23=55\\\\\text{Add 23 to both sides}\\\\26x=78\\\\\text{Divide both sides by 26}\\\\\boxed{\text{x = 3}}$

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You are recreating a scale drawing at a different scale. The original scale is 1 cm : 8 m. The new scale is 1 cm : 2 m. In the o

densk [106]

Answer:

The segment should be 36 centimeters long

Step-by-step explanation:

Let us use the ratio method to solve the question

∵ The original scale is 1 cm : 8 m

∵ In the original drawing, the length of a segment is 9 centimeters

→ By using the ratio method

→ cm : m

→ 1 : 8

→ 9 : x

→ By using the cross multiplication

∵ 1 × x = 9 × 8

∴ x = 72 m

∴ The actual length of the segment is 72 m

∵ The new scale is 1 cm : 2 m

∵ The actual length of the segment is 72 m

→ By using the ratio method

→ cm : m

→ 1 : 2

→ y : 72

→ By using the cross multiplication

∵ y × 2 = 1 × 72

∴ 2y = 72

→ Divide both sides by 2 to find y

∴ y = 36

∴ The drawing length of the segment is 36 cm in the new scale

∴ The segment should be 36 centimeters long

6 0

3 years ago

A rectangle has a length that is 7 inches less that twice it's width. The area of the rectangle is 72 square inches. Write an eq

Nitella [24]

Answer: $2x^2-7x=72$ , where x= width of the rectangle ( in inches).

Step-by-step explanation:

Let x= width of the rectangle ( in inches).

Then its length = 2x-7 ( in inches).

Area of rectangle = Length × width

= (2x-7) × (x)

= 2x × x -7 ×x

= 2x²-7x

The area of the rectangle is 72 square inches.

$\Rightarrow\ 2x^2-7x=72$

Hence, the equation that represents the given situation :

$2x^2-7x=72$

7 0

3 years ago

Use a double angle identity to rewrite the formula r(Θ)=<img src="https://tex.z-dn.net/?f=1%2F16v%5E2sin%28theta%29cos%28theta%2

Artist 52 [7]

Answer:

1/32v²sin2θ

Step-by-step explanation:

Given the expression r(theta) = 1/16v²sinθcosθ

According to double angle of trigonometry identity;

Sin2θ = sin(θ+θ)

Sin2θ = sinθcosθ + cosθsinθ

Sin2θ = 2sinθcosθ

sinθcosθ = sin2θ/2 ... **

Substituting equation ** into the question

1/16v²sinθcosθ = 1/16v²(sin2θ/2)

1/16v²sinθcosθ = 1/2×1/16v²(sin2θ)

1/16v²sinθcosθ = 1/32v²sin2θ

Hence using the double angle identity, the equivalent expression is 1/32v²sin2θ

7 0

3 years ago

Factor 6x^2-4x I need help solving please

horrorfan [7]

Answer:

2x(3x-2)

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

What is the leading coefficient and constant of this problem?<br><br>(8

andrey2020 [161]

2/7*3/8>3/8 because 2/7>1

4 0

4 years ago