All categories

2 years ago

What is the discriminant of the quadratic equation 0 = 2x2 3x – 5?

Mathematics

2 answers:

TiliK225 [7]2 years ago

7 0

Answer:

Step-by-step explanation:

a_sh-v [17]2 years ago

5 0

If you would like to find the discriminant of the quadratic equation 0 = 2x^2 + 3x - 5, you can do this using the following steps:

0 = 2x^2 + 3x - 5
0 = ax^2 + bx + c
a = 2, b = 3, c = - 5

D = b^2 - 4 * a * c = 3^2 - 4 * 2 * (-5) = 9 + 40 = 49

The correct result would be 49.

You might be interested in

Use the diagram to find each angle measure.

tensa zangetsu [6.8K]

Answer:

Jack in Zeta Labs near Facility Intelligence and Zeta Labs spawn (Sells gadgets like the Presence Reduction Module and Night Vision Goggles)

Step-by-step explanation:

8 0

1 year ago

Write a linear equation that contains the ordered pair shown in the table below:

Amiraneli [1.4K]

Answer:

$y=2x-4$

Step-by-step explanation:

Let the equation of line is $y=mx+b$ , where $m$ is the slope of the line.

It passes through $(-5,-14),(-2,-8)\ and\ (1,-2)$ .

(Slope of the line joining $(x_1,y_1)\ and\ (x_2,y_2)=\frac{y_2-y_1}{x_2-x_1}$ )

Hence slope of the given line

$m=\frac{-8(-14)}{-2-(-5)}=\frac{-8+14}{-2+5}=\frac{6}{3}=2$

Equation of line is: $y=2x+b$

The line passes through $(1,-2)$

$-2=2\times 1+b\\b=-2-2\\b=-4$

Check if $(-5,-14)$ is on the line $y=2x-4$

$L.H.S.=-14\\R.H.S.=2\times (-5)-4=-10-4=-14\\L.H.S.=R.H.S.$

Hence line passes through $(5,-14)$ .

Check if $(-2,-8)$ is on the line $y=2x-4$

$L.H.S.=-8\\R.H.S.=2\times (-2)-4=-4-4=-8\\L.H.S.=R.H.S.$

Hence line passes through $(-2,-8)$ .

4 0

2 years ago

What are the solutions to the equation 3(x – 4)(x + 5) = 0?

SVEN [57.7K]

The answer is x=4 or x= minus 5 i mean D.

6 0

2 years ago

(3.2 x 10^14) (5.1 x 10^2) in scientific notation

tresset_1 [31]

Those expressions are already in scientific notation.

6 0

2 years ago

Which is the best first step to write this in standard form?

goldenfox [79]

Answer:

Set the function equal to 0

Step-by-step explanation:

Standard Form of the Quadratic Equation

The form

$ax^2+bx+c=0$

is called the standard form of a quadratic equation. It can be clearly identified the terms of a second-degree polynomial equated to 0.

The equation is given in the form:

$2(x-4)^2-3=8$

And we need to operate the expression to make it look like a standard form. The first logical step should be to set the function equal to 0 and then start to operate the resulting expression. It can be done by subtracting 8 on both sides of the equation:

$2(x-4)^2-3-8=0$

Answer: Set the function equal to 0

4 0

2 years ago