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Lapatulllka [165]
3 years ago
6

Ashton had 28 1/2feet of wrapping paper. He uses 3/8

Mathematics
1 answer:
sammy [17]3 years ago
4 0

Answer:

Step-by-step explanation.

here is a trick

try turning both fractions into a decimal and then divide then. It will be much easier.

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Two boats started to move towards each other from two boat stations, located 30 miles apart. One boat moved at a speed of 3 mile
Ganezh [65]

Answer: <u>3 hours and 20 minutes</u>

Step-by-step explanation:

3x + 2(3)x = 30

3x + 6x     = 30

9x             = 30

9/9           = 30/9

x = 3 1/3 hours

6 0
3 years ago
sid and Jill hiked 4 1/8 miles in the morning and 1 1/7 miles in the afternoon.how many times as far did they hike in the mornin
mote1985 [20]
Your answer is ..
First,
we have to turn our mixed fractions into an improper fraction.
=4 1/8 which is 33/8(4 x 8 + 1).

Our next mixed fraction,
we have 1 1/7 which is 8/7(1 x 7 + 1).

Now, we have the get the same denominator in order to subtract.
SO, both 8 and 7 goes in to 56. So we multiply both mixed fractions to get the same denominator.
(Tip: what ever you do to do numerator, you do to the denominator; and the other way around).
33/8 : 33*7=231 and our denominator, 8*7=56
So our improper fraction now,
231/56

Our next fraction 8/7,
7*8= 56 and our numerator 8*8=64.
=64/56

So, now we subtract.
231-64= 167 and our common denominator. 167/56

Now we divide 167 by 56 which is 2 and remainder is 55.
So, you should end up with a mixed fraction, 2 55/56.

7 0
3 years ago
What model describes the relationship between miles driven and the total cost of a rental car when you pay $50.00 per day and $0
Alex_Xolod [135]
This is a linear equation with y-intercept $50 and slope $0.25/mile:

TC = $50 + ($0.25)x, where x is the number of miles driven.

7 0
3 years ago
Read 2 more answers
What is the area of the region bounded between the curves y=x and y=sqrt(x)?
erastova [34]

Answer:

\frac{1}{6}

Step-by-step explanation:

y = x     .....(1)

y=\sqrt{x}     .... (2)

By solving equation (1) and equation (2)

x = \sqrt{x}

\sqrt{x}\left ( \sqrt{x}-1 \right )=0

\sqrt{x}=0 or \left ( \sqrt{x}-1 \right )=0

x = 0, x = 1

y = 0, y = 1

A = \int_{0}^{1}ydx(curve)-\int_{0}^{1}ydx(line)

A = \int_{0}^{1}\sqrt{x}dx-\int_{0}^{1}xdx

A = \frac{2}{3}[x^\frac{3}{2}]_{0}^{1}-\frac{1}{2}[x^2]_{0}^{1}

A = \frac{2}{3}-\frac{1}{2}

A = \frac{1}{6}

8 0
3 years ago
PLS HELP PLS HELP ASAP
shutvik [7]

Answer:

This was an accident, can you delete this? Sorry

Step-by-step explanation:

3 0
3 years ago
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