Answer:
the answer is 2 + i.
Step-by-step explanation:
Let the square root of 3 + 4i be x + iy.
So (x + iy) (x +iy) = 3 +4i
=> x^2 + xyi + xyi + i^2*y^2 = 3 + 4i
=> x^2 – y^2 + 2xyi = 3 + 4i
Equate the real and complex terms
=> x^2 - y^2 = 3 and 2xy = 4
2xy = 4
=> xy = 2
=> x = 2/y
Substitute in
=> x^2 - y^2 = 3
=> 4/y^2 - y^2 = 3
=> 4 – y^4 = 3y^2
=> y^4 + 3y^2 – 4 = 0
=> y^4 + 4y^2 – y^2 – 4 =0
=> y^2(y^2 + 4) – 1(y^2 + 4) =0
=> (y^2 – 1) (y^2 + 4) =0
Therefore y^2 = 1, we ignore y^2 = -4 as it gives complex values of y.
Therefore y = 1 and x = 2/1 = 2
The required square root of 3 + 4i is 2 + i.
Answer:
12.5
Step-by-step explanation:
x = 2.5
5( 2.5 )
12.5
hopefully this helps you out
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-5(r - 6) + 3(-8 + 8r) = -32
STEP 1: Simplify both sides of the equation.
<span><span><span><span><span><span>(<span>−5</span>)</span><span>(r)</span></span>+<span><span>(<span>−5</span>)</span><span>(<span>−6</span>)</span></span></span>+<span><span>(3)</span><span>(<span>−8</span>)</span></span></span>+<span><span>(3)</span><span>(<span>8r</span>)</span></span></span>=<span>−32 </span></span>(Distribute)
<span><span><span><span><span><span>−<span>5r</span></span>+30</span>+</span>−24</span>+<span>24r</span></span>=<span>−32</span></span><span><span><span>(<span><span>−<span>5r</span></span>+<span>24r</span></span>)</span>+<span>(<span>30+<span>−24</span></span>)</span></span>=<span>−32 </span></span>(Combine Like Terms)
<span><span><span>19r</span>+6</span>=<span>−32</span></span><span><span><span>19r</span>+6</span>=<span>−32
</span></span>
STEP 2: Subtract 6 from both sides.
<span><span><span><span>19r</span>+6</span>−6</span>=<span><span>−32</span>−6</span></span><span><span>19r</span>=<span>−<span>38
STEP 3: Divide both sides by 19.
19r/19 = -38/19
r = -2
FINAL ANSWER: r = -2</span></span></span>
