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3 years ago

6

ken finished 1/5 of his chores before breakfast and 3/5 of his chores after breakfast what fraction of his chores does he have f

inished altogether

1 answer:

xxMikexx [17]3 years ago

5 0

Answer:

4/5

Step-by-step explanation:

1/5 + 3/5 = 4/5

when adding fractions you don't add the denominators

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Plsss help with this question pls with whole procedure pls help

rjkz [21]

i hope this helps.......

7 0

3 years ago

The first hexagon is dilated to form the second hexagon. Select answers from the drop-down menus to correctly complete the state

Varvara68 [4.7K]

Answer:

Scale factor = 4 and it represents an 'enlargement'.

Step-by-step explanation:

We are given a hexagon which is dilated to form the second hexagon.

Now, as the size of the original hexagon is 0.2 units and the size of the dilated hexagon is 0.8 units.

As we get that 0.2 × 4 = 0.8

Therefore. it can seen that the original hexagon is dilated by 4 units in order to obtain new hexagon.

Moreover, dilation refers to the transformation that changes the size of the image.

Now, as we are changing the size by a scale factor of 4. So, this dilation is increasing the size of the original hexagon.

Hence, this dilation represents an enlargement.

7 0

3 years ago

Read 2 more answers

Traffic flow is traditionally modeled as a Poisson distribution.A traffic engineer monitors the traffic flowing through an inter

babymother [125]

Answer:

There is a 6.07% probability that during next 2 min exactly 5 cars passing an intersection are from state.

Step-by-step explanation:

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

$e = 2.71828$ is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

A traffic engineer monitors the traffic flowing through an intersection with an average of 6 cars per minute. So in 2 minutes, 12 cars are expected to flow through the intersection.

If 75% of vehiclesare from state, what is the probability that during next 2 min exactly 5 cars passing an intersection are from state?

We want to know how many of these cars are from state. In 2 minutes, 0.75*12 = 9 cars from the state are expected to pass the intersection, so $\mu = 9$ .

We want to find P(X = 2).

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 5) = \frac{e^{-9}*9^{5}}{(5)!} = 0.0607$

There is a 6.07% probability that during next 2 min exactly 5 cars passing an intersection are from state.

7 0

3 years ago

Which is best estimate of each percent? 21/ of 387?

Phoenix [80]

81.27 is the answer to 21% of 387 so a good estimate would be 82

3 0

3 years ago

The elevation of city A is 72 feet above sea level; the elevation of City C is 24 feet above sea level. The elevation of city D

emmasim [6.3K]

Answer:

<h2> D=C/4</h2>

Step-by-step explanation:

Given that elevation of the cities are

A=72 feet

C=24 feet

D=1/4 of C

The expression for the elevation of city D is

D=C/4

substituting C=24 in the expression we have

D=24/4

D=6

The answer is positive because the elevation is above sea level

7 0

3 years ago