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victus00 [196]
3 years ago
5

A plumber's daily earnings have a mean of $145 per day with a standard deviation of $16.50.

Mathematics
1 answer:
avanturin [10]3 years ago
7 0

Step-by-step explanation:

The plumber's daily earnings have a mean of $145 per day with a standard deviation of

$16.50.

We want to find the probability that the plumber earns between $135 and

$175 on a given day, if the daily earnings follow a normal distribution.

That is we want to find P(135 <X<175).

Let us convert to z-scores using

z =  \frac{x -  \mu}{ \sigma}

This means that:

P(135  \: <  \: X  \: <  \: 175) = P( \frac{135 - 145}{16.5}  \: <  \:  z \:  <  \frac{175 - 145}{ 16.5} )

We simplify to get:

P(135  \: <  \: X  \: <  \: 175) = P(  - 0.61\: <  \:  z \:  <  1.82 )

From the standard n normal distribution table,

P(z<1.82)=0.9656

P(z<-0.61)=0.2709

To find the area between the two z-scores, we subtract to obtain:

P(-0.61<z<1.82)=0.9656-0.2709=0.6947

This means that:

P(135  \: <  \: X  \: <  \: 175) =0.69

The correct choice is C.

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On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove
gogolik [260]

Velocity, distance and time:

This question is solved using the following formula:

v = \frac{d}{t}

In which v is the velocity, d is the distance, and t is the time.

On the first day of travel, a driver was going at a speed of 40 mph.

Time t_1, distance of d_1, v = 40. So

v = \frac{d}{t}

40 = \frac{d_1}{t_1}

The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles

On the second day, the velocity is v = 60.

On the first day, he drove 2 more hours, which means that for the second day, the time is: t_1 - 2

On the first day, he traveled 20 more miles, which means that for the second day, the distance is: d_1 - 20

Thus

v = \frac{d}{t}

60 = \frac{d_1 - 20}{t_1 - 2}

System of equations:

Now, from the two equations, a system of equations can be built. So

40 = \frac{d_1}{t_1}

60 = \frac{d_1 - 20}{t_1 - 2}

Find the total distance traveled in the two days:

We solve the system of equation for d_1, which gets the distance on the first day. The distance on the second day is d_2 = d_1 - 20, and the total distance is:

T = d_1 + d_2 = d_1 + d_1 - 20 = 2d_1 - 20

From the first equation:

d_1 = 40t_1

t_1 = \frac{d_1}{40}

Replacing in the second equation:

60 = \frac{d_1 - 20}{t_1 - 2}

d_1 - 20 = 60t_1 - 120

d_1 - 20 = 60\frac{d_1}{40} - 120

d_1 = \frac{3d_1}{2} - 100

d_1 - \frac{3d_1}{2} = -100

-\frac{d_1}{2} = -100

\frac{d_1}{2} = 100

d_1 = 200

Thus, the total distance is:

T = 2d_1 - 20 = 2(200) - 20 = 400 - 20 = 380

The total distance traveled in two days was of 380 miles.

For the relation between velocity, distance and time, you can take a look here: brainly.com/question/14307500

3 0
3 years ago
predict the attendance for minor league baseball in the year 2005. a. 5,208,000 b. 4,495,000 c. 44,950,000 d. 52,080,000
solong [7]

Answer:

c. 44,950,000

Step-by-step explanation:

The following table is missing:

Year   Attendance (millions)  

1985   18.4  

1990   25.2  

1995   33.1  

2000  37.6  

Using a calculator, the line of best fit is obtained. Equation:

y = 1.31x - 2581.6

where y is attendance (in millions)  and <em>x</em> is the year. Replacing with x = 2005 into the equation, we get:

y = 1.31(2005) - 2581.6

y = 44.95 millions or 44,950,000

6 0
3 years ago
Perry connects a blue garden hose and a green garden hose to make one long hose. The blue hose is 10.5 feet. The green hose is 1
swat32

Answer:

22.25 ft long

if you add 10.5 with 11.75 you'll get 22.25

7 0
3 years ago
(-8+1.5)x4/5 <br><br> Help please
fenix001 [56]

Answer:

-5.2

Step-by-step explanation:

-8+1.5 = -6.5

-6.5 * 4/5 = -6.5 * 0.8 = -5.2

7 0
2 years ago
Read 2 more answers
Zoey bought m mangos for $.55 each an a apples for $.89 each. She spent .55m+.89a dollars. What does .55m represent?
svp [43]
The total cost of each mango.
8 0
3 years ago
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