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4 years ago

Pls help pls help pls help

Mathematics

2 answers:

svetoff [14.1K]4 years ago

8 0

The answer is D, 18-3K.

zhenek [66]4 years ago

8 0

Distribute the equation

31+6+8k+-11k+-19

Combine like terms

(8k+-11k)+(31+6+-19)

ANSWER: D. 18-3k

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What is he rate of change of a line that passes through the points (7,-1) and (-1,5)

tino4ka555 [31]

Hello! thanks for asking this question! -0.75 should be your answer. Please tell me if I was right!

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3 years ago

Plz hellp!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

dedylja [7]

Answer:

28.274

Step-by-step explanation:

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3 years ago

The Palue of the digit in the hundredths place is

Harman [31]

Answer:The value of the digit in the hundredths place is 10 times as great as the value of the digit in the tenths place.

Explained: The model shows that your number is 0.11

We have to find what we can multiply to become the 1 in the tenths place. Since they are the same number but in different places, we just multiply it by 10 to change the value.

So, if you multiply 10 by the 1 in the hundredths place, it will get you to the 1 in the tenths place.

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3 years ago

Manav is painting a rectangular room and the dimensions of this room are given by x,y and z feet. Manav takes 8 hours to paint a

zhenek [66]

Answer:

B) 36 cubic feet

Step-by-step explanation:

Dimensions of the room are x, y and z feet. It is given that x = 6 feet.

Manav took 8 hours to paint the wall with dimensions x and z.

This means, in 8 hours Manav painted area = xz = 6z

In 1 hour Manav painted area = $\frac{6z}{8}$

Manav took 4 hours to paint the wall with dimensions y and z.

This means, in 4 hours Manav painted area = yz

In 1 hour Manav painted area = $\frac{yz}{4}$

Manav took 12 hours to paint the ceiling with dimensions x and y.

This means, in 12 hours Manav painted area = xy = 6y

In 1 hour Manav painted the area = $\frac{6y}{12}=\frac{y}{2}$

Since, Manav works at constant rate, this means the worked done in 1 hour in all 3 cases would be the same. So we can write:

$\frac{6z}{8}=\frac{yz}{4}=\frac{y}{2}$

Using the first two equations, we get:

$\frac{6z}{8}=\frac{yz}{4}\\\\ \frac{6}{8}=\frac{y}{4}\\\\ y=\frac{6}{8} \times 4\\\\ y = 3$

Using the last two equations, we get:

$\frac{yz}{4}=\frac{y}{2}\\\\ \frac{z}{4}=\frac{1}{2}\\\\z=2$

So, we have the follwoing dimensions of the room:

x = 6 feet

y = 3 feet

z = 2 feet

So the volume of the room is = 6 x 3 x 2 = 36 cubic feet

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3 years ago

Zach has a basic cell phone plan that does not include texting. He is going to add a multimedia texting package to his

Vedmedyk [2.9K]

Zach have to send 300 number of multimedia texts for the same cost in two packages.

Step-by-step explanation:

Package A charges $0.25 per multimedia text with no monthly fees.

Package B charges $0.20 per multimedia text and has a $15 monthly fee.

To frame the equations :

Let x be the any amount of multimedia texts are sent.
Let y be the total cost for using the multimedia package.

Package A Equation :

Total cost = No.of text sent × cost per text.

⇒ y = x × 0.25

⇒ y = 0.25x

∴ The equation of package A is y = 0.25x

Package B Equation :

Total cost = (No.of text sent × cost per text) + Monthly fee

⇒ y = (x × 0.20) + 15

⇒ y = 0.2x + 15

∴ The equation of a package B is y = 0.2x + 15

Now, the question is about how many multimedia texts will Zach have to send each month for the two multimedia texting packages to be the same cost.

⇒ equation of package A = equation of package B

⇒ 0.25x = 0.2x + 15

⇒ 0.25x - 0.2x = 15

⇒ 0.05x = 15

⇒ x = 15 / 0.05

⇒ x = 300

∴ Zach have to send 300 number of multimedia texts for the same cost in two packages.

7 0

3 years ago