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3 years ago

What’s the answer for number 9

Mathematics

1 answer:

-BARSIC- [3]3 years ago

3 0

The answer is C because complimentary is equal to 90 so 24+66 equals 90 and 34+56 equal 90

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PLZ HELP 70 POINTS!!!!!

marin [14]

5^(x+7)=(1/625)^(2x-13)

We move all terms to the left:

5^(x+7)-((1/625)^(2x-13))=0

Domain of the equation: 625)^(2x-13))!=0

x∈R

We add all the numbers together, and all the variables

5^(x+7)-((+1/625)^(2x-13))=0

We multiply all the terms by the denominator

(5^(x+7))*625)^(2x+1-13))-((=0

We add all the numbers together, and all the variables

(5^(x+7))*625)^(2x-12))-((=0

We add all the numbers together, and all the variables

(5^(x+7))*625)^(2x=0

not sure if this is right :/

8 0

3 years ago

Read 2 more answers

Which of the following statements are true about the triangles?

Arisa [49]

Show the triangle in the picture

4 0

2 years ago

Mhmhmhmhmhmhmhmhmhmhmhmh

yarga [219]

Answer:

3.59

Step-by-step explanation:

-×-=+

-2.31+5.9

=3.59

please like and Mark as brainliest

5 0

3 years ago

Use Green's Theorem to calculate the circulation of F =2xyi around the rectangle 0≤x≤8, 0≤y≤3, oriented counterclockwise.

Tamiku [17]

Green's theorem says the circulation of $\vec F$ along the rectangle's border $C$ is equal to the integral of the curl of $\vec F$ over the rectangle's interior $D$ .

Given $\vec F(x,y)=2xy\,\vec\imath$ , its curl is the determinant

$\det\begin{bmatrix}\frac\partial{\partial x}&\frac\partial{\partial y}\\2xy&0\end{bmatrix}=\dfrac{\partial(0)}{\partial x}-\dfrac{\partial(2xy)}{\partial y}=-2x$

So we have

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_D-2x\,\mathrm dx\,\mathrm dy=-2\int_0^3\int_0^8x\,\mathrm dx\,\mathrm dy=\boxed{-192}$

6 0

3 years ago

Please help ASAP please I’ll mark as brainlister

faust18 [17]

Problems

The bottom of the red figure should be long; similar to the top of the blue figure.

The top of the red figure should be the same as the bottom of the blue figure.

Red are: (1, -1), (4, -1), (1, -5), (3, -5), (2, -2), (2, -4), (3, -4), (4, -2), (4, -2)

red points should be:

(1, -1), (3, -1), (1, -5), (4, -5), (2, -2), (2, -4), (4, -4), (3, -2), (3, -2),

7 0

3 years ago