All categories

3 years ago

Explain why (5,-2) and (-2,5) do not represent the same point

1 answer:

7 0

Let A(5,-2) and B(-2, 5)

To get A we have to go 5 units horizontally (5 on the right) and - 2 units vertically, (down 2 ) whereas for B(-2,5):

To get B we have to go -2 units horizontally (2 on the LEFT) and 5 units vertically, (UP 5)

You might be interested in

The swimming pool at lifetime city health and fitness club measures 20 meters in length and 15 meters in width wat is the are of

8_murik_8 [283]

20*15 is 300 meters which is the area

8 0

2 years ago

Read 2 more answers

PLZZZZZZZ HELLPPPP MEEEE I HAVE A HEADACHE WITH THIS<br><br> Find the measure of angle b.

Salsk061 [2.6K]

31) 27
32) 75
33) 74
34) 90 (because it’s a right angle and adds up to 180)

4 0

2 years ago

¡ HELP Plz !<br> Graph this line using the slope and y-intercept:<br> y=1/2x-1

Sladkaya [172]

-1 is your x intercept so the first point is going to be at (0,-1) and from there go up 1 and over to the right 2 and mark another point and so one

8 0

2 years ago

Read 2 more answers

Can somebody tell me how to solve these kind of problems?

Ugo [173]

Answer: 918km^2

Step-by-step explanation:

$area(a): 1700km^2\\percentage(p): 5.75 = \frac{5.75}{100}=0.0575\\years(y): 8$

Let x be the new dimension of the area;

$x=a-(a*p*y)$

$x=(1700km^2)-(1700km^2*0.0575*8)\\x=1700km^2-782km^2\\x=918km^2$

6 0

3 years ago

A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len

Gnom [1K]

Answer:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

$df=n-1=93-1=92$

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0

2 years ago