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Alex17521 [72]
3 years ago
5

Can someone help me on questions 10-15

Mathematics
1 answer:
Mazyrski [523]3 years ago
3 0

Answer:

10. Supplementary

11. Congruent

12. Congruent.

13 . congruent

14 supplement

15 supplementary

<h3>Hope this helps you </h3><h3>Do mark as brainliest! </h3>

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Hope this helps.

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PLEASE HELP ASAP WILL GIVE BRAINLEIST!!
inessss [21]

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3 years ago
A car leaves its garage and travels for 30km on a bearing of 145, then 10 km on a bearing of 250 Calculate a) the distance trave
OverLord2011 [107]

The distance travelled from the starting point is 29 km , the bearing is 344 degree

The missing diagram is attached with the answer.

<h3>What is Bearing Angle ?</h3>

It is the horizontal angle between the object and another object.

It is given that the car starts from point travels for 30km on a bearing of 145, then 10 km on a bearing of 250

(a) the distance travelled from the starting point

It can be understood from the diagram that

To determine the distance , b is to determined4

By applying Cosine rule

b² = a² +c²-2ac cos\rm \theta

b² = 10²  +30²  - 2* 30*10 cos75

b² = 100+900 -600* 0.2588

b² = 100-155.2914

b² = 844.7

b = 29 km

Therefore the distance travelled from the starting point is 29 km.

(b) the bearing of the starting point from the car.

To determine the bearing ,

angle C has to be determined

By sine rule

sin C / c = sin B / b

sin C = sin 75 * 30 / 29

sin C = 0.9970

C = sin⁻¹ 0.9970

C = 85.59 degree

angle C = α +70 degree

α  = 15.59 degree

Bearing = 70 + 20 + 9 0 + 90+74 = 244 degree

To know more about Bearing

brainly.com/question/9214012

#SPJ1

5 0
1 year ago
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