Scale factor=0.75 is enlarge , reduce , or preserve ?

Mathematics

2 answers:

zvonat [6]3 years ago

6 0

Answer:

Reduce

Step-by-step explanation:

It will reduce because the factor is less than 1 so it cannot enlarge and it is not the same as the 1 so it cannot preserve.

never [62]3 years ago

5 0

Answer:

Reduce

Step-by-step explanation:

0.75 would be making the subject smaller because it is less than one.

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Algebraic models grade 12 math college please write the answers without explaining thank you.

Zinaida [17]

From the problem :

$6^4\times6^{-5}$

In multiplying expressions with the same bases, the exponent will be added accordingly.

For example :

$a^m\times a^n=a^{m+n}$

the exponent of a are m and n, and the product will be a raised to the sum of m and n.

Applying this to the problem, we have :

$6^4\times6^{-5}=6^{4-5}=6^{-1}$

The answer is d. 6^-1

6 0

1 year ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

<u>Solution:</u>

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$