Answer:
x = 0.5
Step-by-step explanation:
2x - 3 = - 2 ( add 3 to both sides )
2x = 1 ( divide both sides by 2 )
x = 
= 0.5
Answer:
2 L bottle for 1.69
the unit price for the two liters is cheaper than one for 12 pack
Answer:
2/15
Step-by-step explanation:
Step one:
given data
sample space
1 elephant,
4 bears,
3 cats, and
2 dogs.
sample size= 1+4+3+2= 10
Required:
By selecting without replacement, the probability that she chooses a bear both times
Step two:
the first event= Pr(bear)= 4/10= 2/5
the second event, the sample size is now 9 and the number of bears is now 3
Pr(bear)= 3/9= 1/3
Hence, the probability that she chooses a bear both times
= 2/5*1/3
=2/15
Answer:
7m² + 6m - 1
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
<u>Algebra I</u>
- Combining Like Terms
- Standard Form: ax² + bx + c = 0
Step-by-step explanation:
<u>Step 1: Define expression</u>
7m² + 6m - 1
<u>Step 2: Simplify</u>
<em>The expression cannot be simplified further.</em>
<span>n = 11<span>.
Explanation:
Let m be the number of boxes Mark sells and a be the number of boxes Ann sells.
Since Mark sells 10 less than n, m = n-10. Since Ann sells 2 less than n, a = n-2.
Together, they sold n-10+n-2=2n-12 boxes.
We know that they sold less than n boxes, so our inequality would be
2n-12<n.
To solve this, subtract n from both sides:
2n-12-n<n-n; n-12<0.
Add 12 to both sides:
n-12+12<0+12; n<12.
This means there were less than 12 boxes. The next number down is 11; this woks because Mark sold 10 less than n; 11-10=1. Mark sold at least 1 box.
If n=10, however, 10-10=0; this doesn't work, because Mark did sell at least 1 box. </span></span>
