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3 years ago

30 POINTS HELP PLEASE

Mathematics

2 answers:

erastovalidia [21]3 years ago

6 0

I want to say the answers are (-1,5) and (3,1125)

dem82 [27]3 years ago

3 0

Answer:

answers are (-1,5) and (3,1125)

Step-by-step explanation:

have a good day :)

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IrinaVladis [17]

Answer:

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Explanation:

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3 years ago

Identify the percent of change (POC) as an increase or decrease. Then find the percent of change. Round to the nearest tenth of

Andrej [43]

Percent change=(change/original) tiimes 100 change= |original-new| so 12 to 36 |12-36|=|-24|=24 so pcercent change=100 times (24/12)=100 times 2=200% 50 to 35 |50-35|=|15|=15 percent change=100 times (15/50)=100 times 100 times 0.30=30% 10 to 24 |10-24|=|-14|=14 percent change=100 times (14/10)=100 times 1.4=140% 16 to 44.2 |16-44.2|=|-28.2|=28.2 percent change=100 times (28.2/16)= 100 times 1.7625=176.25% answers are -12 inches to 36 inches: 200% -50 punds to 35 pounds: 30% -10 gallons to 24 gallons: 140% -16 centimeters to 44.2 centimeters: 176.25%

6 0

3 years ago

g Recall the method used to obtain a confidence interval for the difference between two population means for matched samples. (a

Dovator [93]

Answer:

Step-by-step explanation:

Population 1: 11, 7, 9, 12, 13, 15, 15

Population 2: 6, 6, 4, 5, 8, 13, 12

Mean = sum of terms/number of terms

For population 1,

number of terms = 7

Mean = (11 + 7 + 9 + 12 + 13 + 15 + 15)/7 = 82/7 = 11.7

For population 2,

Number of terms = 7

Mean = (6 + 6 + 4 + 5 + 8 + 13 + 12)/7 = 7.71

The difference value for each element is

(11 + 7 + 9 + 12 + 13 + 15 + 15) - (6 + 6 + 4 + 5 + 8 + 13 + 12) = (5, 1, 5, 7, 5, 2, 3)

The difference between the two means is

Mean of population 1 - mean of population 2

Difference = 11.7 - 7.71 = 3.99

8 0

3 years ago

Long division<br> 3x+1/6x^6+5x^5+2x^4-9x^3+7x^2-10x+2

inna [77]

$(6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2) / (3x+1)$

We divide first number from first parenthesis with first number from second parenthesis. Then the resulting number we multiply by all numbers in second parenthesis and substract from first parenthesis.

$6 x^{6}/3x = 2 x^{5} \\ \\ 6 x^{6}+5x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2 - 6 x^{6} -2 x^{5} = 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2\\$

We repeat previous steps until we run out of numbers:
$3x^{5}/3x=x^{4} \\ \\ 3x^{5}+2x^{4}-9x^{3}+7x^{2}-10x+2-3x^{5}-x^{4}= \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2 \\ \\ \\ x^{4}/3x= \frac{1}{3} x^{3} \\ \\ x^{4}-9x^{3}+7x^{2}-10x+2-x^{4}- \frac{1}{3} x^{3}= \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2 \\ \\ \\ - \frac{28}{3} x^{3}/3x= - \frac{28}{9} x^{2} \\ \\ - \frac{28}{3} x^{3}+7x^{2}-10x+2+ \frac{28}{3} x^{3}+ \frac{28}{9} x^{2} = \\ \\ \frac{91}{9} x^{2}-10x+2$
$\frac{91}{9} x^{2}/3x=\frac{91}{27} x \\ \\ \frac{91}{9} x^{2}-10x+2-\frac{91}{9} x^{2}-\frac{91}{27} x= \\ \\ -\frac{361}{27} x+2 \\ \\ \\ -\frac{361}{27} x/3x=-\frac{361}{81} \\ \\ -\frac{361}{27} x+2+\frac{361}{27}x+\frac{361}{27}= \\ \\ \frac{415}{27}$

We are left with a number that has no x inside. This is remainder.
The final solution is sum of all these solutions and remainder:
$(2 x^{5}+x^{4}+\frac{1}{3} x^{3} - \frac{28}{9} x^{2} +\frac{91}{27} x)+(-\frac{361}{81} )$

6 0

3 years ago

Helpp plsss!!!! I've to submit ASAP

alexandr1967 [171]

i don’t rly remember surface area i’m sorry i couldn’t help

8 0

2 years ago

Read 2 more answers