Answer:
value of x = 5.8 mm
Step-by-step explanation:
We have given,
Two right triangles EDH and EDG.
In right triangle EDH, EH = 56mm , DH = 35 mm
Using Pythagoras theorem we can find ED.
i.e EH² = ED²+DH²
56²=ED²+35²
ED²=56²-35²
ED = √(56²-35²) = 7√39 = 43.71 mm
Now, Consider right triangle EDG
Here, EG=44.8mm , GD = x+4 and ED = 7√39
Again using Pythagoras theorem,
EG² = ED² + DG²
44.8²= (7√39)²+ (x+4)²
(x+4)² = 44.8² - (7√39)²
x+4 = √(44.8² - (7√39)²)
x+4 = 9.8
or x = 9.8 - 4 = 5.8 mm
Hence we got the value of x = 5.8 mm
The answer is 46°.
The measure of an inscribed angle is equal to (1/2) the measure of the intercepted arc.
That means that, since ADC is 23 degrees, doubling that gives you 46 degrees, the measure of the intercepted arc.
Central angles are equal to the measure of the intercepted arc, which in this case is the same arc we just calculated.
Therefore it's 46.
Answer:
a=1
Step-by-step explanation:
Multiply all terms by a and cancel:
6+−6a=3+−3a
−6a+6=−3a+3(Simplify both sides of the equation)
−6a+6+3a=−3a+3+3a(Add 3a to both sides)
−3a+6=3
−3a+6−6=3−6(Subtract 6 from both sides)
−3a=−3
−3a
−3
=
−3
−3
(Divide both sides by -3)
a=1
